Individual Income Tax

P1 : Individual Income Tax

Time Limit:10000ms

Case Time Limit:1000ms

Memory Limit:256MB

Description

For incomes from wages and salaries, the progressive tax rate in excess of specific amount is applicable. The income amount taxable shall be the remainder after deducting 3500 yuan from the monthly income. The tax rate is below:

Grade Monthly Taxable Income	Tax Rate(%)
Income of 1,500 yuan or less	3%
That part of income in excess of 1,500 to 4,500 yuan	10%
That part of income in excess of 4,500 to 9,000 yuan	20%
That part of income in excess of 9,000 to 35,000 yuan	25%
That part of income in excess of 35,000 to 55,000 yuan	30%
That part of income in excess of 55,000 to 80,000 yuan	35%
That part of income in excess of 80,000 yuan	45%

Given the tax Little Hi paid, do you know his salary this month?

Input

Line 1: M, the tax Little Hi paid. (1 <= M <= 5,000,000)

Output

Line 1: Little Hi's salary. The number should be rounded dowm to the nearest integer.

Hint

Little Hi's salary is 15692 yuan. The tax is calculated below: The income amount taxable is 15692 - 3500 = 12192 yuan. That part of income of 1500 or less: 1500 * 3% = 45 yuan. That part of income in excess of 1,500 to 4,500 yuan: 3000 * 10% = 300 yuan. That part of income in excess of 4,500 to 9,000 yuan: 4500 * 20% = 900 yuan. That part of income in excess of 9,000 to 35,000 yuan: (12192 - 9000) * 25% = 798 yuan. Total tax is 45 + 300 + 900 + 798 = 2043 yuan.

Sample Input

2043

Sample Output

15692

#include<iostream>
#include<string>
using namespace std;
int main()
{
    float fTaxTotal=0;
    cin >> fTaxTotal;//Input Tax

    if (fTaxTotal>5000000)
        cout << "out of range";
    if (fTaxTotal < 1)
        cout << 0;

    string sResult = "";

    float fTaxPointList[7]; 
    fTaxPointList[0] = 0.03;
    fTaxPointList[1] = 0.10;
    fTaxPointList[2] = 0.20;
    fTaxPointList[3] = 0.25;
    fTaxPointList[4] = 0.30;
    fTaxPointList[5] = 0.35;
    fTaxPointList[6] = 0.45;

    float fTaxList[6];
    fTaxList[0] = (1500-0)*0.03;
    fTaxList[1] = (4500 - 1500)*0.10;
    fTaxList[2] = (9000 - 4500)*0.20;
    fTaxList[3] = (35000 - 9000)*0.25;
    fTaxList[4] = (55000 - 35000)*0.30;
    fTaxList[5] = (80000 - 55000)*0.35;

    float fTaxToComeList[7];
    fTaxToComeList[0] = 0;
    fTaxToComeList[1] = 1500;
    fTaxToComeList[2] = 4500;
    fTaxToComeList[3] = 9000;
    fTaxToComeList[4] = 35000;
    fTaxToComeList[5] = 55000;
    fTaxToComeList[6] = 80000;

    int iTaxLevel=0;
    float fFindTaxTotal = fTaxTotal;
    for (; iTaxLevel < 6; iTaxLevel++)
    {
        fFindTaxTotal -= fTaxList[iTaxLevel];
        if (fFindTaxTotal <= 0)
        {
            break;
        }
    }

    float fIncome = 3500;
    fIncome += fTaxToComeList[iTaxLevel];
    for (int i = 0; i < iTaxLevel;i++)
    {
        fTaxTotal -= fTaxList[i];
    }
    fIncome += fTaxTotal / fTaxPointList[iTaxLevel];

    cout << fIncome;

    return 0;
}

题目给出的答案是满足的，但是结果只有50分，Wrong Answer...还不清楚到底是哪一组的数据会通过不了。