HDOJ：5585

Problem Description

There is a number N.You should output "YES" if N is a multiple of 2, 3 or 5,otherwise output "NO".

 

 

Input

There are multiple test cases, no more than 1000 cases.
For each case,the line contains a integer N.(0<N<1030)

 

 

Output

For each test case,output the answer in a line.

 

 

Sample Input

2 3 5 7

 

 

Sample Output

YES YES YES NO

 

 

 

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string.h>
using namespace std;

int main()
{
char a[40];

while(scanf("%s",a)!=EOF)
{
int i,m,sum,count=0;
m=strlen(a);
sum=0;

for(i=0;i<m;i++){
sum+=a[i]-'0';
}

if(sum%3==0)//判断能否被3整除
{
cout<<"YES"<<endl;
count=1;//用于输出
}
else
{
sum=0;
sum=a[m-1]-'0';
if(sum%2==0||sum%5==0)//判断
{
cout<<"YES"<<endl;
count=1;//用于输出
}

}

if(count==0)
cout<<"NO"<<endl;
}

return 0;
}