HDOJ1727 Hastiness

题目啊：http://acm.hdu.edu.cn/showproblem.php?pid=1727

 

我的方法很笨，不知道有没有什么好方法~~~

 

这道题说实话，也不是很水，要考虑的方面其实很多的，我调了好半天，终于由WA变为AC，不容易啊~~~

 

AC代码：

#include<stdio.h> char s[10][10]={"zero","one","two","three","four","five","six","seven","eight","nine"}; char p[10][10]={"zero","ten","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"}; char q[10][10]={"ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"}; int main(){ int t,a[4],i,temp,len,cnt; while(scanf("%d",&t)!=EOF){ a[0]=a[1]=a[2]=a[3]=0; temp=t; i=0; cnt=0;//记录整型数的位数； while(temp>0){ a[i++]=temp%10; temp/=10; cnt++; } if(cnt==4){ printf("%s thousand",s[a[3]]); if(a[2]!=0){ printf(" and %s hundred",s[a[2]]); } if(a[1]!=0&&a[0]!=0){ if(a[1]>1){ printf(" and %s-%s",p[a[1]],s[a[0]]); } else{ printf(" and %s",q[a[0]]); } } else if(a[1]==0&&a[0]!=0){ printf(" and %s",s[a[0]]); } else if(a[1]!=0&&a[0]==0){ printf(" and %s",p[a[1]]); } printf("/n"); } else if(cnt==3){ printf("%s hundred",s[a[2]]); if(a[1]!=0&&a[0]!=0){ if(a[1]>1){ printf(" and %s-%s",p[a[1]],s[a[0]]); } else{ printf(" and %s",q[a[0]]); } } else if(a[1]==0&&a[0]!=0){ printf(" and %s",s[a[0]]); } else if(a[1]!=0&&a[0]==0){ printf(" and %s",p[a[1]]); } printf("/n"); } else if(cnt==2){ if(a[1]>1){ printf("%s",p[a[1]]); if(a[0]!=0){ printf("-%s",s[a[0]]); } } else{ printf("%s",q[a[0]]); } printf("/n"); } else if(cnt==1){ printf("%s/n",s[a[0]]); } else{ printf("zero/n"); } } }