自己实现memcpy

//memcpy()函数的模拟实现
#include<assert.h>
#include<stdio.h>
 
void* my_memcpy(void* destination, const void* source, size_t num)
{
    assert(destination);        //断言防止函数接收空指针进行操作
    assert(source);
 
    void* ret = destination;
    while (num--)
    {
        *(char*)destination = *(char*)source;
        destination = (char*)destination + 1;
        source = (char*)source + 1;
    }
 
    return ret;
}
 
int main()
{
    int arr1[] = { 1,2,3,4,5,6,7,8,9,10 };
    int arr2[10] = { 0 };
    //使用my_memcpy()函数将arr1数组的前20字节(即前5个整形)拷进arr2中
    my_memcpy(arr2, arr1, 20);
 
    for (int i = 0; i < 10; i++)
        printf("%d\n", arr2[i]);
 
    return 0;
}