OKHttpUtil搞定Http请求

一、OKHttpUtil 功能

• 根据URL自动判断是请求HTTP还是HTTPS，不需要单独写多余的代码。
• 默认情况下Cookie自动记录，比如可以实现模拟登录，即第一次访问登录URL后后续请求就是登录状态。
• 自动识别304跳转并二次请求
• 支持代理配置
• 支持referer配置
• 支持User-Agent配置
• 自动识别并解压Gzip格式返回内容
• 支持springboot 配置文件
• 极简的封装调用

二、OKHttpUtil使用

1、 maven引入

<dependency>
    <groupId>io.github.admin4j</groupId>
    <artifactId>http</artifactId>
    <version>0.4.0</version>
</dependency>

2、GET请求

最简单的使用莫过于用HttpUtil工具类快速请求某个接口：

Response response = HttpUtil.get("https://github.com/search", Pair.of("q", "okhttp"));
System.out.println("response = " + response);

3、POST请求

一行代码即可搞定，当然Post请求也很简单：

# JSON 格式的body
Response post = HttpUtil.post("https://oapi.dingtalk.com/robot/send?access_token=27f5954ab60ea8b2e431ae9101b1289c138e85aa6eb6e3940c35ee13ff8b6335", "{\"msgtype\": \"text\",\"text\": {\"content\":\"【反馈提醒】我就是我, 是不一样的烟火\"}}");
System.out.println("post = " + post);

# form 请求
Map<String, Object> formParams = new HashMap<>(16);
formParams.put("username", "admin");
formParams.put("password", "admin123");
Response response = HttpUtil.postForm("http://192.168.1.13:9100/auth/login",
                formParams
);
System.out.println("response = " + response);

　返回格式为JSON的 可以使用 HttpJsonUtil 自动返回JsonObject　

JSONObject object=HttpJsonUtil.get("https://github.com/search",
Pair.of("q","http"),
Pair.of("username","agonie201218"));
System.out.println("object = "+object);

4、文件上传

File file=new File("C:\\Users\\andanyang\\Downloads\\Sql.txt");
Map<String, Object> formParams=new HashMap<>();
formParams.put("key","test");
formParams.put("file",file);
formParams.put("token","WXyUseb-D4sCum-EvTIDYL-mEehwDtrSBg-Zca7t:qgOcR2gUoKmxt-VnsNb657Oatzo=:eyJzY29wZSI6InpoYW56aGkiLCJkZWFkbGluZSI6MTY2NTMwNzUxNH0=");
Response response=HttpUtil.upload("https://upload.qiniup.com/",formParams);
System.out.println(response);

5、下载文件

HttpUtil.down("https://gitee.com/admin4j/common-http","path/");

6、HttpRequest 链式请求

# get
Response response=HttpRequest.get("https://search.gitee.com/?skin=rec&type=repository")
.queryMap("q","admin4j")
.header(HttpHeaderKey.USER_AGENT,"admin4j")
.execute();
System.out.println("response = "+response);

# post form
Response response=HttpRequest.get("http://192.168.1.13:9100/auth/login")
.queryMap("q","admin4j")
.header(HttpHeaderKey.USER_AGENT,"admin4j")
.form("username","admin")
.form("password","admin123")
.execute();
System.out.println("response = "+response);