4.16上机作业

1.有10个评委打分,(去掉一个最高一个最低)求平均分。

package gr;

import java.util.*;

public class hy {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		int[] a = new int[10];
		System.out.println("输入10个分数");
		Scanner input = new Scanner(System.in);
		for (int i = 0; i < a.length; i++) {
			int x = input.nextInt();
			a[i] = x;

		}
		for (int i = 0; i < a.length - 1; i++) {
			for (int j = 0; j < a.length - 1 - i; j++) {
				if (a[j] > a[j + 1]) {
					int temp = a[j];
					a[j] = a[j + 1];
					a[j + 1] = temp;
				}
			}
		}

		int sum = 0;
		for (int i = 0; i < a.length; i++) {
			sum = a[1] + a[2] + a[3] + a[4] + a[5] + a[6] + a[7] + a[8];

		}
		System.out.println("" + sum / 8);
	}
}

  

 

2.自学一下Java随机数,生成一个长度为10的随机数组(每个数的范围是0~99),排序后输出。

package gr;
import java.util.Random;
public class hy {
    public static void main(String[] args) {
        // TODO Auto-generated method stubint 
        int[] a = new int[10];
        Random r=new Random();
        for (int i = 0; i < a.length; i++) {
            a[i]=r.nextInt(100);
        }
        int t;
        for (int i = 0; i < a.length - 1; i++) {
            for (int j = 0; j < a.length-1-i; j++) {
                if (a[j + 1] < a[j]) {
                    t = a[j];
                    a[j] = a[j + 1];
                    a[j + 1] = t;
                }
            }
        }
        for (int i : a) {
            System.out.println(i);
        }
    }
}

  

 

3.制作彩票35选7程序。 (就是1~35随机生成7个不重复的数)

package gr;

import java.util.Random;

public class hy {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Random r = new Random();
		for (int j = 0; j <= 7; j++) {
			int k = r.nextInt(35);
			System.out.println(k);

		}

	}

}

  4.定义一个长度为10的int数组,统计数组中的最大值、最小值、以及奇数和偶数的个数

package gr;

public class hy {
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int a[] = {85,30,47,96,28,46};
        int max = a[0];
        int min = a[0];
        int countQ = 0;
        int countO = 0;
        for (int i = 0; i < a.length; i++) {
            if (a[i]>max) {
                max = a[i];
            }
            if (a[i]<min) {
                min = a[i];
            }
            if (a[i]%2==0) {
                countQ += 1;
            }else {
                countO += 1;
            }
        }
        System.out.println("数组的最大值为:" + max);
        System.out.println("数组的最小值为:" + min);
        System.out.println("数组的偶数个数为:" + countO);
        System.out.println("数组的奇数个数为:" + countQ);
    }
}

  

 

posted @ 2020-04-16 13:49  王志将  阅读(122)  评论(0编辑  收藏  举报