上机作业
1.定义长度位5的整型数组,输入他们的值,用冒泡排序后输出.
package gr;
import java.util.Scanner;
public class hy {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input=new Scanner(System.in);
System.out.println("输入数组的值:");
int[] a= new int[5];
for(int i=0;i<a.length;i++) {
a[i]=input.nextInt();
}
for (int i = 0; i < a.length-1; i++) {
for (int j = 0; j < a.length-1-i; j++) {
if(a[j] > a[j+1]){
int t=a[j];
a[j]= a[j+1];
a[j+1] = t;
}
}
}
System.out.println("冒号排序为:");
for (int i=0;i<a.length;i++) {
System.out.println(a[i]+" ");
}
}
}
2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在,输出下标,不存在输出"not found"
package gr;
import java.util.Scanner;
public class hy {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input=new Scanner(System.in);
boolean c=false;
int[] x=new int[]{34,22,35,67,45,66,12,33};
System.out.print("请输出一个数");
int a=input.nextInt();
for(int i=0;i<x.length;i++){
if(x[i]==a){
System.out.println("该数存在于数组中下标为"+i);
c=true;
}
} if(c==false){
System.out.println("not found");
}
}
}
3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值。
package gr;
import java.util.Scanner;
public class hy {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);
double[][]arr={{2,8,3,9},{8,4,6,7},
{11,22,88,66},{34,25,68,42},
{78,54,93,42}};
for(int i=0;i<arr.length;i++){
System.out.println();
for(int j=0;j<arr.length-1;j++){
System.out.print(arr[i][j]+" ");
}
}
}
}
4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值.
package gr;
public class hy {
public static void main(String[] args) {
// TODO Auto-generated method stub
int [][]a={{87,36,89,54},{7,64,25,46},{58,12,49,62}};
int max=a[0][0];
for(int i=0;i<3;i++){
for(int j=0;j<4;j++){
if(a[i][j]>max){
max=a[i][j];
}
}
}
System.out.println(max);
}
}

浙公网安备 33010602011771号