第六次作业

1编写程序，使用while语句求和sum=1+3+5+…+21

#include<stdio.h>

main()

{

        int i=1,sum=0;

        while(i<=21)

        {

                 sum+=i;

                 i+=2;

        }

        printf("%d\n",sum);

}

 

 

2.编写程序，使用while语句求和sum=1+1/3+1/5+..+1/n

#include<stdio.h>

main()

{

        int i=1,n;

        double sum=0;

        scanf("%d",&n);

        while(i<=n)

        {

                 sum+=1.0/i;

                 i+=2;

        }

        printf("sum=%f\n",sum);

}

 

 

3编写程序，使用do-while语句求阶乘f=1*2*3*..*n

#include<stdio.h>

main()

{

        int i=1,n,sum=1;

        scanf("%d",&n);

        while(i<=n)

        {

                 sum*=i;

                 i++;

        }

        printf("%d\n",sum);

}

 

 

4.打印出所有的水仙花数

#include<stdio.h>

main()

{

        int i=100,ge,shi,bai;

        while(i<=999){

                 ge=i%10;

                 shi=i/10%10;

                 bai=i/100;

                 if(i==ge*ge*ge+shi*shi*shi+bai*bai*bai)

                         printf("%4d",i);

                 i++;

        }

}

 

 

5.输入两个数,输出他们中间的数

#include<stdio.h>

main()

{

        int a,b,i;

        scanf("%d%d",&a,&b);

        i=a+1;

        while(i<=b-1){

                 printf("%d",i); 

        i++;

        }

}

 

 

6.输出1-100既能被3又能被5整除的数的和

#include<stdio.h>

main()

{

        int n,i=0,sum=0;

        scanf("i%3==o&&i%5==o",i);

        while(i<=100){

                 sum+=i;

                 printf("%d",i); 

        i++;

        }

}