Find Minimum in Rotated Sorted Array

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

You may assume no duplicate exists in the array.

 

class Solution {
public:
    int findMin(vector<int>& nums) {
        int left = 0;
        int right = nums.size()-1;
        int mid;
        while(left < right){
            mid = (right+left)/2;
            if(nums[mid] > nums[right])
                left = mid + 1;
            else
                right = mid;
        }
        return nums[left];
    }
};