LeetCode - Remove Duplicates from Sorted List
Description:Given a sorted linked list, delete all duplicates such that each element appear only once.
For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3.
给一个有序链表,删除重复的元素。还是首先考虑head == null的情况。
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode deleteDuplicates(ListNode head) {
if(head == null)
return null;
ListNode p, q;
q = head;
p = head.next;
while(p != null) {
if(p.val == q.val) {
q.next = p.next;
p.next = null;
p = q.next;
}
else {
p = p.next;
q = q.next;
}
}
return head;
}
}
作者:Pickle
声明:对于转载分享我是没有意见的,出于对博客园社区和作者的尊重一定要保留原文地址哈。
致读者:坚持写博客不容易,写高质量博客更难,我也在不断的学习和进步,希望和所有同路人一道用技术来改变生活。觉得有点用就点个赞哈。








浙公网安备 33010602011771号