LeetCode - Majority Element
参考了别人的想法,思路简洁,效率高。虽然是在充分理解别人的思路后写出的代码,但是还是发现了自己的不足之处。以后还是要多思考多写。加油吧!
public class Solution { public int majorityElement(int[] num) { int ans = 0, cnt = 0; for(int i=0; i<num.length; i++) { if(cnt == 0) { ans = num[i]; cnt ++; } else { if(ans == num[i]) { cnt ++; } else { cnt --; } } } return ans; } }
作者:Pickle
声明:对于转载分享我是没有意见的,出于对博客园社区和作者的尊重一定要保留原文地址哈。
致读者:坚持写博客不容易,写高质量博客更难,我也在不断的学习和进步,希望和所有同路人一道用技术来改变生活。觉得有点用就点个赞哈。
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