第七讲:输入输出与模版
作业习题解答
习题地址:http://cxsjsx.openjudge.cn/hw202007/
A:简单的SumArray
#include <iostream>
#include <string>
using namespace std;
template <class T>
T SumArray(T* a,T* b){
T c= *a;
for(T* i=a+1;i<b;i++)
c+= *i;
return c;
}
int main() {
string array[4] = { "Tom","Jack","Mary","John"};
cout << SumArray(array,array+4) << endl;
int a[4] = { 1, 2, 3, 4}; //提示:1+2+3+4 = 10
cout << SumArray(a,a+4) << endl;
return 0;
}
B:简单的foreach
#include <iostream>
#include <string>
using namespace std;
template<class T1,class T2>
void MyForeach(T1* m, T1* n,T2 h ) {
for (int i = 0; i < n-m; i++)
h(*(s + i));
}
void Print(string s)
{
cout << s;
}
void Inc(int & n)
{
++ n;
}
string array[100];
int a[100];
int main() {
int m,n;
while(cin >> m >> n) {
for(int i = 0;i < m; ++i)
cin >> array[i];
for(int j = 0; j < n; ++j)
cin >> a[j];
MyForeach(array,array+m,Print);
cout << endl;
MyForeach(a,a+n,Inc);
for(int i = 0;i < n; ++i)
cout << a[i] << ",";
cout << endl;
}
return 0;
}
C:简单的Filter
#include <iostream>
#include <string>
using namespace std;
template<class T1,class T2>
T1* Filter(T1*a,T1*b,T1*c,T2 f)
{
for(T1*p=a;p<b;p++)
{
if(f(*p))
{
*c=*p;
c++;
}
}
return c;
}
bool LargerThan2(int n)
{
return n > 2;
}
bool LongerThan3(string s)
{
return s.length() > 3;
}
string as1[5] = {"Tom","Mike","Jack","Ted","Lucy"};
string as2[5];
int a1[5] = { 1,2,3,4,5};
int a2[5];
int main() {
string * p = Filter(as1,as1+5,as2,LongerThan3);
for(int i = 0;i < p - as2; ++i)
cout << as2[i];
cout << endl;
int * p2 = Filter(a1,a1+5,a2,LargerThan2);
for(int i = 0;i < p2-a2; ++i)
cout << a2[i] << ",";
return 0;
}
D:你真的搞清楚为啥 while(cin >> n) 能成立了吗?
注:operator bool () 提供一个本类型到bool的隐式转换,不允许使用参数。
#include <iostream>
using namespace std;
class MyCin
{
bool flag;
public:
MyCin():flag(true){}
MyCin &operator>>(int &n){
if(!flag) return*this;//不再把第二个数读入
cin>>n;
if(n==-1) flag=false;
return *this;
}
operator bool(){return flag;}
};
int main()
{
MyCin m;
int n1,n2;
while( m >> n1 >> n2)
cout << n1 << " " << n2 << endl;
return 0;
}
E:山寨版istream_iterator
为什么ccin一定要引用?
#include <iostream>
#include <string>
using namespace std;
template <class T>
class CMyistream_iterator
{
private:
T value;
public:
istream &ccin;
CMyistream_iterator(istream &_ccin):ccin(_ccin){
ccin>>value; //读入第一个数
}
T operator *(){
return this->value;
}
void operator++ (int){ //后置++多一个参数
ccin>>value;
}
};
int main()
{
int t;
cin >> t;
while( t -- ) {
CMyistream_iterator<int> inputInt(cin);
int n1,n2,n3;
n1 = * inputInt; //读入 n1
int tmp = * inputInt;
cout << tmp << endl;
inputInt ++;
n2 = * inputInt; //读入 n2
inputInt ++;
n3 = * inputInt; //读入 n3
cout << n1 << " " << n2<< " " << n3 << " ";
CMyistream_iterator<string> inputStr(cin);
string s1,s2;
s1 = * inputStr;
inputStr ++;
s2 = * inputStr;
cout << s1 << " " << s2 << endl;
}
return 0;
}
F:这个模板并不难
#include <iostream>
#include <string>
#include <cstring>
using namespace std;
template <class T>
class myclass {
private:
T* p;int size;
public:
myclass(T* a,int b)
{
p=new T[b+1];
size=b;
for(int i=0;i<size;i++)
p[i]=a[i];
p[size]=0;
}
~myclass( ) {
delete [] p;
}
void Show()
{
for( int i = 0;i < size;i ++ ) {
cout << p[i] << ",";
}
cout << endl;
}
};
int a[100];
int main() {
char line[100];
while( cin >> line ) {
myclass<char> obj(line,strlen(line));;
obj.Show();
int n;
cin >> n;
for(int i = 0;i < n; ++i)
cin >> a[i];
myclass<int> obj2(a,n);
obj2.Show();
}
return 0;
}
G:排序,又见排序!
#include <iostream>
using namespace std;
bool Greater2(int n1,int n2)
{
return n1 > n2;
}
bool Greater1(int n1,int n2)
{
return n1 < n2;
}
bool Greater3(double d1,double d2)
{
return d1 < d2;
}
template <class T1,class T2>
void mysort(T1*start,T1*end,T2 p){
for(int i=1;i<=end-start-1;i++)
{
for(int j=0;j<end-start-i;j++)
{
if(!p(start[j],start[j+1]))
{
T1 temp=start[j];
start[j]=start[j+1];
start[j+1]=temp;
}
}
}
}
#define NUM 5
int main()
{
int an[NUM] = { 8,123,11,10,4 };
mysort(an,an+NUM,Greater1); //从小到大排序
for( int i = 0;i < NUM; i ++ )
cout << an[i] << ",";
mysort(an,an+NUM,Greater2); //从大到小排序
cout << endl;
for( int i = 0;i < NUM; i ++ )
cout << an[i] << ",";
cout << endl;
double d[6] = { 1.4,1.8,3.2,1.2,3.1,2.1};
mysort(d+1,d+5,Greater3); //将数组从下标1到下标4从小到大排序
for( int i = 0;i < 6; i ++ )
cout << d[i] << ",";
return 0;
}

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