JSON 在Ajax数据交换中的简单运用
随着浏览器内核更新,原先的json.js在最新的谷歌浏览下不管用了,运行报错,特此修改下代码,不使用json.js,使用Object自带的json转换方法,修改时间,2016年10月26日.
首先需要创建一个Servlet类,命名为JSONTest.java. 然后配置下web.xml文件,我的是自动生成的,也就没改动.web.xml的内容如下:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>JSONTest</servlet-name>
<servlet-class>servlet.ajax.JSONTest</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>JSONTest</servlet-name>
<url-pattern>/servlet/JSONTest</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
接下来,就是创建JS文件了,命名为yulei.js,其中的url是访问上面的servlet的路劲.js内容如下:
function Car(make,model,year,color){
this.make=make;
this.model=model;
this.year=year;
this.color=color;
}
function sendRequest(){
var car=new Car('Dodge','Cornet R\T',2009,'yellow');
// var pars="car="+car.toJSONString();
var pars="car="+Object.toJSON(car);
var url="servlet/JSONTest";
var mailAjax= new Ajax.Request(
url,
{
method:'get',
parameters:pars,
onComplete:jsonResponse,
onException: function(x, e) { alert(e) }
}
);
}
function jsonResponse(originalRequest){
alert(originalRequest.responseText);
var myObj=originalRequest.responseText.parseJSON();
alert(myObj.name);
}
然后,新建一个jsonTest.jsp文件,里面主要是加载一些js文件,和一个按钮,内容如下:
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%> <% String path = request.getContextPath(); String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/"; %> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <base href="<%=basePath%>"> <title>My JSP 'jsonTest.jsp' starting page</title> <meta http-equiv="pragma" content="no-cache"> <meta http-equiv="cache-control" content="no-cache"> <meta http-equiv="expires" content="0"> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="This is my page"> <!-- <link rel="stylesheet" type="text/css" href="styles.css"> --> <script type="text/javascript" src="js/prototype.js"></script> <!-- <script type="text/javascript" src="js/json.js"></script> --> <script type="text/javascript" src="js/yulei.js"></script> </head> <body> This is my JSP page. <br> <input type="button" value="测试" onclick="sendRequest()"/> </body> </html>
最后,我们就编写Servlet类的内容:
package servlet.ajax;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.json.JSONException;
import org.json.JSONObject;
public class JSONTest extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
request.setCharacterEncoding("UTF-8");
response.setCharacterEncoding("UTF-8");
PrintWriter out = response.getWriter();
String s3=request.getParameter("car");
System.out.println(s3);
try {
JSONObject jsonObject=new JSONObject(s3);
System.out.println(jsonObject.getString("model"));
System.out.println(jsonObject.getString("year"));
} catch (JSONException e) {
e.printStackTrace();
}
JSONObject resultJSON=new JSONObject();
try {
resultJSON.append("name", "violet");
resultJSON.append("occupation", "developer");
resultJSON.append("age", new Integer(22));
} catch (JSONException e) {
e.printStackTrace();
}
out.print(resultJSON.toString());
}
}这个Servlet的功能是:首先获取前台JS ajax请求传来的JSON数据,将其中的某些属性打印出来(你也可以Debug查看),然后重新新建一个JSON对象,并将其以字符串的形式传到前台,我们就可以获取到这个新建的JSON数据.
这就是简单的JSON在AJAX请求中数据传输的作用.
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