poj 1952 最长公共子序列计数

  看代码就懂了  不解释  3 1 1 1 1 2 2 2 1 1 1 3  第一个3 和最后一个 3 只需要一个就够了,,,

 1 #include<iostream>
 2 #include<cstring>
 3 #include<algorithm>
 4 #include<stdio.h>
 5 #include<cmath>
 6 using namespace std;
 7 
 8 int dp[5005],num[5005],arr[5005];
 9 int main( )
10 {
11     int N; scanf("%d",&N);
12         for( int i = 1; i <= N; i++ )
13         {
14             scanf("%d",&arr[i]);
15             dp[i] = num[i] = 1;
16         }
17         int Max = 0;
18         for( int i = 2; i <= N; i++ )
19         for( int j = i-1; j >= 1; j-- )
20         if( arr[i] < arr[j] )
21         {
22             if( dp[j]+1 > dp[i] )
23             {
24                  dp[i] =  dp[j]+1;
25                 num[i] = num[j];
26             }else if( dp[j]+1 == dp[i] )
27                 num[i] += num[j];
28         }else if( arr[i] == arr[j] )
29         {
30             if( dp[i] == 1 )num[i] = 0;
31             break;
32         }
33         for( int i = 1; i <= N; i++ )
34         Max = max( Max,dp[i] );
35         int res = 0;
36         for( int i = 1; i <= N; i++ )
37         if( dp[i] == Max )res+=num[i];
38         cout<<Max<<" "<<res<<endl;
39     return 0;
40 }
View Code

 

posted on 2013-10-10 20:34  浪舟  阅读(161)  评论(0编辑  收藏  举报

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