实验4

任务一
#include <stdio.h>
#include<stdlib.h>
#define N 4
int main() {

    int a[N] = { 1, 9, 8, 4 };
    char b[N] = { '1', '9', '8', '4' };
    int i;
    printf("sizeof(int) = %d\n", sizeof(int));
    printf("sizeof(char) = %d\n", sizeof(char));
    printf("\n");

    for (i = 0; i < N; ++i)
        printf("%p: %d\n", &a[i], a[i]);
    printf("\n");

    for (i = 0; i < N; ++i)
        printf("%p: %c\n", &b[i], b[i]);
    printf("\n");

    printf("a = %p\n", a);
    printf("b = %p\n", b);
    system("pause");
    return 0;
}

1.2

#include <stdio.h>
#include<stdlib.h>
#define N 2
#define M 4
int main() {
    int a[N][M] = { {1, 9, 8, 4}, {2, 0, 2, 2} };
    char b[N][M] = { {'1', '9', '8', '4'}, {'2', '0', '2', '2'} };
    int i, j;
    
    for (i = 0; i < N; ++i)
        for (j = 0; j < M; ++j)
            printf("%p: %d\n", &a[i][j], a[i][j]);

    printf("\n");
    
    for (i = 0; i < N; ++i)
        for (j = 0; j < M; ++j)
            printf("%p: %c\n", &b[i][j], b[i][j]);
    system("pause");
    return 0;
}

任务二

#include <stdio.h>
#include<stdlib.h>
#define N 13

int days_of_year(int year, int month, int day);

int main() {
    int year, month, day;
    int days;

    while (scanf_s("%d%d%d", &year, &month, &day) != EOF) {
        days = days_of_year(year, month, day);
        printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days);
    }
    system("pause");
    return 0;
}

// 函数定义
// 补足函数days_of_year的定义
int days_of_year(int year, int month, int day) {
    int a[13], ans, i;
    a[0] = 29;
    a[1] = 31;
    a[2] = 28;
    a[3] = 31;
    a[4] = 30;
    a[5] = 31;
    a[6] = 30;
    a[7] = 31;
    a[8] = 31;
    a[9] = 30;
    a[10] = 31;
    a[11] = 30;
    a[12] = 31;
    ans = day;
    if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) {
        if (month > 2)
            ans++;
        for (i = 1; i < month; i++)
            ans += a[i];
    }
    else
        for (i = 1; i < month; i++)
            ans += a[i];
    return ans;
}

任务三

#include <stdio.h>
#include<stdlib.h>
#define N 5


void input(int x[], int n);
void output(int x[], int n);
double average(int x[], int n);
void bubble_sort(int x[], int n);

int main() {
    int scores[N];
    double ave;

    printf("录入%d个分数:\n", N);
    input(scores, N);

    printf("\n输出课程分数: \n");
    output(scores, N);

    printf("\n课程分数处理: 计算均分、排序...\n");
    ave = average(scores, N);
    bubble_sort(scores, N);

    printf("\n输出课程均分: %.2f\n", ave);
    printf("\n输出课程分数(高->低):\n");
    output(scores, N);
    system("pause");
    return 0;
}

// 函数定义
// 输入n个整数保存到整型数组x中 
void input(int x[], int n) {
    int i;

    for (i = 0; i < n; ++i)
        scanf_s("%d", &x[i]);
}

// 输出整型数组x中n个元素 
void output(int x[], int n) {
    int i;

    for (i = 0; i < n; ++i)
        printf("%d ", x[i]);
    printf("\n");
}

// 计算整型数组x中n个元素均值,并返回 
double average(int x[], int n) {
    int i;
    double ans = 0;
    for (i = 0; i < n; i++) {
        ans += x[i];
    }
    return ans / n;
}


// 对整型数组x中的n个元素降序排序
void bubble_sort(int x[], int n) {
    int i, j, t;
    for (i = 0; i < n - 1; i++)
        for (j = 0; j < n - 1; j++)
            if (x[j] < x[j + 1]) {
                t = x[j + 1];
                x[j + 1] = x[j];
                x[j] = t;
            }
}

任务四

#include <stdio.h>
#define N 100
void dec2n(int x, int n); // 函数声明

int main() {
    int x;

    printf("输入一个十进制整数: ");
    while (scanf_s("%d", &x) != EOF) {
        dec2n(x, 2);  // 函数调用: 把x转换成二进制输出
        dec2n(x, 8);  // 函数调用: 把x转换成八进制输出
        dec2n(x, 16); // 函数调用: 把x转换成十六进制输出

        printf("\n输入一个十进制整数: ");
    }

    return 0;
}

// 函数定义
// 功能: 把十进制数x转换成n进制,打印输出
void dec2n(int x, int n) {
    char dict[100] = { '0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F' };
    char ans[N] = { '0' };
    int i, k = 0;
    while (1) {
        if (x / n == 0) {
            i = x % n;
            ans[k] = dict[i];
            k++;
            x = x / n;
            break;
        }
        else {
            i = x % n;
            ans[k] = dict[i];
            k++;
            x = x / n;
        }
    }
    for (; k >= 0; k--)
        printf("%c", ans[k]);
    printf("\n");
}

任务五

#include <stdio.h>#define N 100void func(int x[][N], int n);void output(int x[][N], int n); int main(){
    int x[N][N];
    int i, j, n;
    printf("Enter n: ");
    while (scanf_s("%d", &n) != EOF) {
        func(x, n); 
        output(x, n); 
        printf("\nEnter n: ");
    }
    return 0;
}
void output(int x[][N], int n) {
    int i, j;
    for (i = 0; i < n; ++i) {
        for (j = 0; j < n; ++j)
            printf("%5d", x[i][j]);
        printf("\n");
    }
}void func(int x[][N], int n)
{
    int i, j;
    for (i = 0; i < n; i++)
        for (j = 0; j < n; j++)
            if (i <= j)
                x[i][j] = i+1;
            else
                x[i][j] = j+1;
}

任务六

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>

#define N 80

int main() {
    char views1[N] = "hey, C, I have not love u yet.";
    char views2[N] = "hey, C, how can I love u?";
    char t[N];

    printf("交换前: \n");
    printf("views1: %s\n", views1);
    printf("views2: %s\n", views2);

    // 交换
    strcpy(t, views1);
    strcpy(views1, views2);
    strcpy(views2, t);

    printf("交换后: \n");
    printf("views1: %s\n", views1);
    printf("views2: %s\n", views2);

    return 0;
}

6.2

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>

#define N 80

int main() {
    char views[2][N] = { "hey, C, I have not love u yet.",
                         "hey, C, how can I love u?" };

    char t[N];

    printf("交换前: \n");
    printf("views1: %s\n", views[0]);
    printf("views2: %s\n", views[1]);

    // 交换
    strcpy(t, views[0]);
    strcpy(views[0], views[1]);
    strcpy(views[1], t);

    printf("交换后: \n");
    printf("views1: %s\n", views[0]);
    printf("views2: %s\n", views[1]);

    return 0;
}

任务七

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>

#define N 5
#define M 20

void bubble_sort(char str[][M], int n); // 函数声明

int main() {
    char name[][M] = { "Bob", "Bill", "Joseph", "Taylor", "George" };
    int i;

    printf("输出初始名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);

    printf("\n排序中...\n");
    bubble_sort(name, N);  // 函数调用 

    printf("\n按字典序输出名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);

    return 0;
}

// 函数定义
// 功能:使用冒泡排序算法对二维数组str中的n个字符串按字典序排序
// 补足函数bubble_sort()实现 
// ×××
void bubble_sort(char str[][M], int n)
{
    int i, j;
    char x[100];
    for (i = 0; i < n - 1; ++i)
    {
        for (j = 0; j < n - i - 1; ++j)
        {
            if (strcmp(str[j], str[j + 1]) > 0)
            {
                strcpy(x, str[j]);
                strcpy(str[j], str[j + 1]);
                strcpy(str[j + 1], x);
            }
        }

    }

}

 

posted @ 2022-11-29 21:42  15468483  阅读(3)  评论(0编辑  收藏  举报