bfs判断子图是否连通

int judge() {
	int v[13] = { 0 };
	queue<int> myq;
	myq.push(ans[0]);
	v[ans[0]] = 1;
	while (!myq.empty()) {
		int t = myq.front();
		myq.pop();
		for (int i = 1; i < 5; i++) {
			if (c[t][ans[i]] == 1 && v[ans[i]] == 0) {
				myq.push(ans[i]);
				v[ans[i]] = 1;
				sum--;
			}
		}
	}
	if (sum == 0)
		return 1;
	else
		return 0;
}
posted @ 2019-03-16 17:54  阳离子  阅读(217)  评论(0编辑  收藏  举报