用户三次登录（python day01）

流程图

 

#!/usr/bin/env python
# -*-coding: utf-8 -*-
# author:wolf
#import os,sys,getpass
import sys
i=0
while i<3:
    name=input('please input your name:')  #输入用户名
    lock_file=open('lock_user','r+')  #打开被禁用的用户的记录库
    lock_list=lock_file.readlines() #逐行读取其内容
    for lock_line in lock_list:    #轮询每一行的内容
        lock_name=lock_line.strip('\n') #去掉行尾的换行符
        if name ==lock_name:   #判断输入的用户名是否是禁用的用户
            sys.exit('the user is locked!')
    user_file=open('user_db','r+') #打开用户密码库
    user_list=user_file.readlines()  #逐行读取其内容
    for user_line in user_list:
       # print(user_line)
        (user,password)= user_line.strip('\n').split()#按默认的空格符切片每一行的内容
        if  user==name:
            j=0
            while j<3: #判断密码是否正常，最多输入三次，对于三次不正确该账号被锁定
                password2 = input('please input your password:')
                if password2==password:
                    sys.exit('login suceed,congratulations!')
                else:
                    k=2-j
                    print('wrong password,you have %s times chance,please try again!'%k)
                    j+=1
            lock_file = open('lock_user', 'a+') #把锁定的账号追加到账号锁定库稳定的后面一行
            lock_file.write('\n'+name)
            sys.exit('your have input wront password more than 3 times,the user is locked,please contact administrator ')
    print('this user is not exit ,please try again')
    i=i+1
    user_file.close()
    lock_file.close()
sys.exit('you have input 3 times wrong user,byebye!') #输入三次不存在的账号名，程序结束