Dijkstra邻接矩阵板子

const int N = 510;//节点个数
int n;
int g[N][N];//图
int dist[N];//距离
bool st[N];//判断点是否访问过
int dijkstra(int s)//s表示起点,求s到任意点的最短距离
{
    memset(dist, 0x3f, sizeof dist);
    dist[s] = 0;
    for (int i = 0; i < n; i ++ )
    {
        int t = -1;
        for (int j = 0; j < n; j ++ )
            if (!st[j] && (t == -1 || dist[t] > dist[j]))
                t = j;
        for (int j = 0; j < n; j ++ )
            dist[j] = min(dist[j], dist[t] + g[t][j]);
        st[t] = true;
    }
    if (dist[n] == 0x3f3f3f3f) return -1;
    return dist[n];
}

  

posted @ 2024-03-26 15:16  wockcow  阅读(7)  评论(0)    收藏  举报