【算法】KY111日期差值

描述
有两个日期,求两个日期之间的天数,如果两个日期是连续的我们规定他们之间的天数为两天

输入描述:
有多组数据,每组数据有两行,分别表示两个日期,形式为YYYYMMDD

输出描述:
每组数据输出一行,即日期差值
示例1

输入:
20110412
20110422

输出:
11

#include<stdio.h>
using namespace std;

void nextDay(int &year, int &month, int &day) {
	int dayOfMonth[] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
	int isLeap = (year % 400 == 0) || (year % 4 == 0 && year % 100 != 0);
	// isLeap is Leap Year is 1 
	isLeap ? dayOfMonth[2] = 29 : dayOfMonth[2] = 28;
	day++;
	//
	if (day > dayOfMonth[month]) {
		month++;
		day = 1;
	}
	// 
	if (month > 12) {
		year++;
		month = 1;
	} 
} 

/*
20011202
20011226
25
*/
int main() {
	int year, month, day;
	int year1, month1, day1;
	while(scanf("%4d%2d%2d\n%4d%2d%2d", &year, &month, &day, &year1, &month1, &day1)!=-1) {
		int count = 1;	// 起始天数为1 
		while (year!=year1 || month!=month1 || day!=day1 ) {
			nextDay(year, month, day);
			count++;
		}
		printf("%d",count);
	}

	return 0;
} 
posted @ 2024-03-07 17:07  Lnnau  阅读(29)  评论(0)    收藏  举报  来源