实验1 C语言开发环境使用和数据类型、运算符、表达式
#include<stdio.h> int main(){ printf(" o \n"); printf("<H> \n"); printf("I I \n"); printf("\n"); printf(" o \n"); printf("<H> \n"); printf("I I \n"); return 0; } #include<stdio.h> int main(){ printf(" o \t o\n"); printf("<H> \t<H>\n"); printf("I I \tI I\n"); return 0; } #include<stdio.h> int main(){ int x,y; int r1,r2,r3,r4; x = 1; y = 2; r1 = x + y; r2 = x - y; r3 = x * y; r4 = x / y; printf("r1 = %d\n",r1); printf("r2 = %d\n",r2); printf("r3 = %d\n",r3); printf("r4 = %d\n",r4); return 0; } #include<stdio.h> int main(){ float x,y; float r1,r2,r3,r4; x = 1; y = 2; r1 = x + y; r2 = x - y; r3 = x * y; r4 = x / y; printf("r1 = %f\n",r1); printf("r2 = %f\n",r2); printf("r3 = %f\n",r3); printf("r4 = %f\n",r4); return 0; } #include<stdio.h> int main(){ int n,r1,r2,r3,r4; n = 100; r1 = n*(n+1)/2; r2 = (n+1)*n/2; r3 = n/2*(n+1); r4 = (n+1)/2*n; printf("n = %d\n",n); printf("r1 = %d\n",r1); printf("r2 = %d\n",r2); printf("r3 = %d\n",r3); printf("r4 = %d\n",r4); return 0; } #include<stdio.h> int main(){ int n,r1,r2,r3,r4; n = 101; r1 = n*(n+1)/2; r2 = (n+1)*n/2; r3 = n/2*(n+1); r4 = (n+1)/2*n; printf("n = %d\n",n); printf("r1 = %d\n",r1); printf("r2 = %d\n",r2); printf("r3 = %d\n",r3); printf("r4 = %d\n",r4); return 0; } #include<stdio.h> int main(){ int a1,a2,a3; char c1,c2,c3; double x,y; scanf("%d%d%d",&a1,&a2,&a3); printf("%d,%d,%d\n",a1,a2,a3); scanf("%c%c%c",&c1,&c2,&c3); printf("%c%c%c\n",c1,c2,c3); scanf("%lf,%lf",&x,&y); printf("%f,%f",x,y); return 0; } #include<stdio.h> int main(){ int a1,a2; char c1,c2; scanf("%d%c%d%c",&a1,&c1,&a2,&c2); printf("a1 = %d,a2 = %d\n",a1,a2); printf("c1 = %c,c2 = %c\n",c1,c2); return 0; } #include<stdio.h> int main(){ int answer; char words[5000]; printf("网课让一些人欢喜一些人忧。\n"); printf("1.作为一个宅,社恐,觉得这样很好,有网络,自主学习,很 ok .\n"); printf("2.不喜,不喜,很不喜,眼睛快瞎了,脑壳有点卡……\n"); printf("3.中间派,不知道,说不清.\n"); printf("4.其它……\n"); printf("你的选择:"); scanf("%d",&answer); if (answer == 4){ printf("请补充说明你的想法:\n"); getchar(); gets ( words ); } printf("\n"); printf("网当遇到问题时,你会选择:\n"); printf("1.遇到问题,就解决问题。不懂的,探索式学习,逐个攻破。\n"); printf("2.遇到问题, 不高兴。然后,…,没有了.\n"); printf("3.其它……\n"); printf("你的选择:"); scanf("%d",&answer); if (answer == 1) printf(":)\n"); else if(answer == 2) printf("这样不能解决问题啊……我们选择1好不好:)\n"); else if(answer == 3) { printf("请补充说明你的想法:\n"); getchar(); gets ( words ); } return 0; } #include<stdio.h> int main(){ int answer; char words[5000]; printf("网课让一些人欢喜一些人忧。\n"); printf("1.作为一个宅,社恐,觉得这样很好,有网络,自主学习,很 ok .\n"); printf("2.不喜,不喜,很不喜,眼睛快瞎了,脑壳有点卡……\n"); printf("3.中间派,不知道,说不清.\n"); printf("4.其它……\n"); printf("你的选择:"); scanf("%d",&answer); if (answer == 4){ printf("请补充说明你的想法:\n"); gets ( words ); } printf("\n"); printf("网当遇到问题时,你会选择:\n"); printf("1.遇到问题,就解决问题。不懂的,探索式学习,逐个攻破。\n"); printf("2.遇到问题, 不高兴。然后,…,没有了.\n"); printf("3.其它……\n"); printf("你的选择:"); scanf("%d",&answer); if (answer == 1) printf(":)\n"); else if(answer == 2) printf("这样不能解决问题啊……我们选择1好不好:)\n"); else if(answer == 3) { printf("请补充说明你的想法:\n"); gets ( words ); } return 0; } #include<stdio.h> int main() { int answer; char words[5000]; printf("你喜欢宠物吗?\n"); printf("1.喜欢\n"); printf("2.不喜欢\n") ; scanf("%d",&answer); if (answer == 1){ printf("你喜欢猫还是狗或是其它?\n"); getchar(); gets (words); } else if(answer == 2){ printf("为什么呢?\n"); getchar(); gets (words); } return 0; }




整型/整型=整型 失去部分精度


n/2 (n+1)/2在n取奇数和偶数时分别会因整型/整型=整型 失去部分精度





getchar使回答完问题按下回车键后代码再继续进行

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