js基础面试题-用js递归的方式写1到100求和 

<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
  <meta http-equiv="content-type" content="text/html;charset=utf-8">
  <title></title>
  <script src="./Scripts/jquery-1.8.3.min.js" type="text/javascript"></script>
  <body>
    <script language="javascript">
      function add(num1,num2) {
        var num =num1+num2;
         if (num2+1>100) {
          return num;
         }
         else{
          return add(num,num2+1)
         }
      }
      var sum= add(1,2);
      console.log('sum',sum);
    </script>
  </body>
</html>

　　

posted @ 2022-01-24 10:37  挥不去的执念  阅读(216)  评论(0)    收藏  举报