实验6 C语言结构体和枚举应用编程

实验4

源代码

 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 #define N 10
 4 
 5 typedef struct {
 6     char isbn[20];          
 7     char name[80];          
 8     char author[80];       
 9     double sales_price;    
10     int  sales_count;       
11 } Book;
12 
13 void output(Book x[], int n);
14 void sort(Book x[], int n);
15 double sales_amount(Book x[], int n);
16 
17 int main() {
18      Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
19                   {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
20                   {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
21                   {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 
22                   {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
23                   {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
24                   {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
25                   {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
26                   {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
27                   {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
28     
29     printf("图书销量排名(按销售册数): \n");
30     sort(x, N);
31     output(x, N);
32 
33     printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
34     system("pause");
35     return 0;
36 }
37 
38 void output(Book x[], int n){
39     int i;
40     printf("%-20s %-30s %-20s %-8s %s\n", "ISBN号", "书名", "作者", "售价", "销售册数");
41     for (i = 0; i < n; i++){
42         printf("%-20s %-30s %-20s %.1f     %d\n",
43                x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
44     }
45 }
46 
47 
48 void sort(Book x[], int n){
49     int i, j;
50     Book temp;
51     for (i = 0; i < n - 1; i++){
52         for (j = 0; j < n - 1 - i; j++){
53             if (x[j].sales_count < x[j+1].sales_count){
54                 temp = x[j];
55                 x[j] = x[j+1];
56                 x[j+1] = temp; }
57         }
58     }
59 }
60 
61 
62 double sales_amount(Book x[], int n){
63     double total = 0;
64     int i;
65     for (i = 0; i < n; i++)
66         total += x[i].sales_price * x[i].sales_count;
67     return total;
68 }
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运行截图

4552ae25-fcdb-4ce0-8ac3-e15472e97b01

 

实验5

源代码

 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 
 4 typedef struct {
 5     int year;
 6     int month;
 7     int day;
 8 } Date;
 9 
10 void input(Date *pd);                   
11 int day_of_year(Date d);                
12 int compare_dates(Date d1, Date d2);    
13                                      
14 
15 void test1() {
16     Date d;
17     int i;
18 
19     printf("输入日期:(以形如2025-12-19这样的形式输入)\n");
20     for(i = 0; i < 3; ++i) {
21         input(&d);
22         printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
23     }
24 }
25 
26 void test2() {
27     Date Alice_birth, Bob_birth;
28     int i;
29     int ans;
30 
31     printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n");
32     for(i = 0; i < 3; ++i) {
33         input(&Alice_birth);
34         input(&Bob_birth);
35         ans = compare_dates(Alice_birth, Bob_birth);
36         
37         if(ans == 0)
38             printf("Alice和Bob一样大\n\n");
39         else if(ans == -1)
40             printf("Alice比Bob大\n\n");
41         else
42             printf("Alice比Bob小\n\n");
43     }
44 }
45 
46 int main() {
47     printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
48     test1();
49 
50     printf("\n测试2: 两个人年龄大小关系\n");
51     test2();
52     system("pause");
53     return 0;
54 }
55 
56 void input(Date *pd) {
57     scanf("%d-%d-%d", &pd->year, &pd->month, &pd->day);
58 }
59 
60 int day_of_year(Date d) {
61     int month_days[] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
62     int total = 0;
63     int i;
64     for(i = 1; i < d.month; i++) {
65         total += month_days[i];
66     }
67     total += d.day;
68     if( (d.year % 4 == 0 && d.year % 100 != 0) || (d.year % 400 == 0) ) {
69         if(d.month > 2) {
70             total += 1;
71         }
72     }
73     return total;
74 }
75 
76 int compare_dates(Date d1, Date d2) {
77     if(d1.year < d2.year) return -1;
78     if(d1.year > d2.year) return 1;
79     if(d1.month < d2.month) return -1;
80     if(d1.month > d2.month) return 1;
81     if(d1.day < d2.day) return -1;
82     if(d1.day > d2.day) return 1;
83     return 0;
84 }
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运行截图

 df567aaf-93a7-426c-bb02-a07faa7cd2c8

 

实验6

源代码

 1 #include <stdio.h>
 2 #include <string.h>
 3 #include<stdlib.h>
 4 
 5 enum Role {admin, student, teacher};
 6 
 7 typedef struct {
 8     char username[20];  
 9     char password[20];  
10     enum Role type;    
11 } Account;
12 
13 void output(Account x[], int n);   
14 
15 int main() {
16     Account x[] = {{"A1001", "123456", student},
17                     {"A1002", "123abcdef", student},
18                     {"A1009", "xyz12121", student}, 
19                     {"X1009", "9213071x", admin},
20                     {"C11553", "129dfg32k", teacher},
21                     {"X3005", "921kfmg917", student}};
22     int n;
23     n = sizeof(x)/sizeof(Account);
24     output(x, n);
25     system("pause");
26     return 0;
27 }
28 
29 void output(Account x[], int n) {
30     int i, j;
31     int pwd_len;
32     for (i = 0; i < n; i++){
33         printf("%-10s", x[i].username);
34         pwd_len = strlen(x[i].password);
35         for (j = 0; j < pwd_len; j++)
36             printf("*");
37         printf("\t\t");
38 
39         switch (x[i].type) {
40             case admin:
41                 printf("admin\n");
42                 break;
43             case student:
44                 printf("student\n");
45                 break;
46             case teacher:
47                 printf("teacher\n");
48                 break;
49         }
50     }
51 }
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运行截图

 2320029f-b1ed-4e82-807d-efddacecfddd

 

实验7

源代码

 1 #include <stdio.h>
 2 #include <string.h>
 3 #include <stdlib.h>
 4 
 5 typedef struct {
 6     char name[20];      
 7     char phone[12];     
 8     int  vip;          
 9 } Contact; 
10 
11 
12 void set_vip_contact(Contact x[], int n, char name[]); 
13 void output(Contact x[], int n);    
14 void display(Contact x[], int n);  
15 
16 
17 #define N 10
18 int main() {
19     Contact list[N] = {{"刘一", "15510846604", 0},
20                        {"陈二", "18038747351", 0},
21                        {"张三", "18853253914", 0},
22                        {"李四", "13230584477", 0},
23                        {"王五", "15547571923", 0},
24                        {"赵六", "18856659351", 0},
25                        {"周七", "17705843215", 0},
26                        {"孙八", "15552933732", 0},
27                        {"吴九", "18077702405", 0},
28                        {"郑十", "18820725036", 0}};
29     int vip_cnt, i;
30     char name[20];
31 
32     printf("显示原始通讯录信息: \n"); 
33     output(list, N);
34 
35     printf("\n输入要设置的紧急联系人个数: ");
36     scanf("%d", &vip_cnt);
37     
38     printf("输入%d个紧急联系人姓名:\n", vip_cnt);
39     for(i = 0; i < vip_cnt; ++i) {
40         scanf("%s", name);
41         set_vip_contact(list, N, name);
42     }
43 
44     printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
45     display(list, N);
46     system("pause");
47     return 0;
48 }
49 
50 void set_vip_contact(Contact x[], int n, char name[]) {
51     int i;
52     for (i = 0; i < n; i++) {
53         if (strcmp(x[i].name, name) == 0) 
54             x[i].vip = 1;
55     }
56 }
57 
58 void display(Contact x[], int n) {
59     int i, j;
60     Contact temp;
61     for (i = 0; i < n - 1; i++) {
62         for (j = 0; j < n - 1 - i; j++) {
63             int swap_flag = 0;
64             if (x[j].vip < x[j+1].vip) 
65                 swap_flag = 1;
66             else if (x[j].vip == x[j+1].vip && strcmp(x[j].name, x[j+1].name) > 0) 
67                 swap_flag = 1;
68             if (swap_flag) {
69                 temp = x[j];
70                 x[j] = x[j+1];
71                 x[j+1] = temp;}
72         }
73     }
74     output(x, n);
75 }
76 
77 void output(Contact x[], int n) {
78     int i;
79 
80     for(i = 0; i < n; ++i) {
81         printf("%-10s%-15s", x[i].name, x[i].phone);
82         if(x[i].vip)
83             printf("%5s", "*");
84         printf("\n");
85     }
86 }
View Code

 

运行截图

 98602d31-1413-4258-b3c5-48aa7f5001ed

实验总结

初步掌握了结构体、枚举类型的定义与使用方法，结合自定义函数实现排序、统计、查询等功能，对结构化程序设计有了新的理解。

posted @ 2026-06-15 21:27  wf-585  阅读(4)  评论(0)    收藏  举报