获取URL参数

handleURL(url) {
const urlARG = location.search.slice(1).split('&');
const urlVAL = urlARG.find(n => n.startsWith(`${url}=`)).split('=')[1];
return urlVAL;
}

 

https://i.cnblogs.com/EditPosts.aspx?opt=1

 

handleURL('opt');

// 1