python 递归遍历目录筛选特定文件名的文件

#!/usr/bin/python

import os
import sys


list=[]
folder_path="/root"
def search_files(folder_path):

    search_string = "测试"

    for root, dirs, files in os.walk(folder_path):

        for name in files:

            if search_string  in name:

                f = os.path.join(root, name)
                list.append(f)
    print(list)

search_files(folder_path)

　　

python 234.py
['/root/测试123.xlsx', '/root/123/测试99ee.xlsx', '/root/123/345/测试999.txt']