erlang des cbc 

1 B5 = crypto:block_encrypt(des_cbc, "12345678", <<0:64>>, "87654321").
2 %<<56,84,48,40,155,117,148,36>>
3 crypto:block_decrypt(des_cbc, "12345678", <<0:64>>, B5).
4 %<<"87654321">>

 

posted @ 2015-04-25 21:40  尾巴儿  阅读(322)  评论(0)    收藏  举报