/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
vector<TreeNode*> ans;
int n;
bool flag[1007];
bool dfs(TreeNode* now){
if (now==NULL)
return false;
if (dfs(now->left)) //下层被删去
now->left=NULL;
if (dfs(now->right))
now->right=NULL;
if (flag[now->val]){
if ((now->left)!=NULL)
ans.push_back(now->left);
if ((now->right)!=NULL)
ans.push_back(now->right);
return true;
}
return false;
}
class Solution {
public:
vector<TreeNode*> delNodes(TreeNode* root, vector<int>& to_delete) {
ans.clear();
n=to_delete.size();
memset(flag,0,sizeof(flag));
bool check=false;
for (int i=0;i<n;i++){
flag[to_delete[i]]=true;
if (to_delete[i]==(root->val))
check=true;
}
if (!check)
ans.push_back(root);
dfs(root);
return ans;
}
};