实验4

任务1

#include <stdio.h>
#define N 4
int main() 
{
    int a[N] = { 1, 9, 8, 4 };
    char b[N] = { '1', '9', '8', '4' };
    int i;
    printf("sizeof(int) = %d\n", sizeof(int));
    printf("sizeof(char) = %d\n", sizeof(char));
    printf("\n");
    // 输出一维int数组a中每个元素的地址、值
    for (i = 0; i < N; ++i)
        printf("%p: %d\n", &a[i], a[i]);
    printf("\n");
    // 输出一维char数组b中每个元素的地址、值
    for (i = 0; i < N; ++i)
        printf("%p: %c\n", &b[i], b[i]);
    printf("\n");
    // 输出数组名a和b对应的值
    printf("a = %p\n", a);
    printf("b = %p\n", b);
    return 0;
}

是 4 是 1 相等

#include <stdio.h>
#define N 2
#define M 4
int main() {
    int a[N][M] = { {1, 9, 8, 4}, {2, 0, 2, 2} };
    char b[N][M] = { {'1', '9', '8', '4'}, {'2', '0', '2', '2'} };
    int i, j;
    // 输出二维数组a中每个元素的地址和值
    for (i = 0; i < N; ++i)
        for (j = 0; j < M; ++j)
            printf("%p: %d\n", &a[i][j], a[i][j]);
    printf("\n");
    // 输出二维数组a中每个元素的地址和值
    for (i = 0; i < N; ++i)
        for (j = 0; j < M; ++j)
            printf("%p: %c\n", &b[i][j], b[i][j]);
    return 0;
}

是4 是 1

任务2

#include <stdio.h>
#define N 13
int days_of_year(int year, int month, int day);
int main() {
    int year, month, day;
    int days;
    while (scanf_s("%d%d%d", &year, &month, &day) != EOF) {
        days = days_of_year(year, month, day);
        printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days);
    }
    return 0;
}
int days_of_year(int year, int mounth, int day)
{
    int  days,leap;
    int a[N] = {0,31,59,90,120,151,181,212,243,273,304,334};
    days = a[mounth - 1] + day;
    if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0))
        leap = 1; 
    else
        leap = 0; 
    if (leap == 1 && mounth > 2)
    {
        days++;
    }
    return days;
}

实验3

#include <stdio.h>
#define N 5
void input(int x[], int n);
void output(int x[], int n);
double average(int x[], int n);
void bubble_sort(int x[], int n);
int main() {
    int scores[N];
    double ave;
    printf("录入%d个分数:\n", N);
    input(scores, N);
    printf("\n输出课程分数: \n");
    output(scores, N);
    printf("\n课程分数处理: 计算均分、排序...\n");
    ave = average(scores, N);
    bubble_sort(scores, N);
    printf("\n输出课程均分: %.2f\n", ave);
    printf("\n输出课程分数(高->低):\n");
    output(scores, N);
    return 0;
}
void input(int x[], int n) {
    int i;
    for (i = 0; i < n; ++i)
        scanf_s("%d", &x[i]);
}
void output(int x[], int n) {
    int i;
    for (i = 0; i < n; ++i)
        printf("%d ", x[i]);
    printf("\n");
}
double average(int x[], int n)
{
    int i, sum=0;
    double ave;
    for (i = 0; i < n; ++i)
        sum += x[i];
    ave = sum / n;
    return ave;
    printf("\n");
}

void bubble_sort(int x[], int n)
{
    int i,j,t;
    for (i = 0; i < n; ++i)
    {
        for (j = 0; j < n - i; j++)
        {
            if (x[j] < x[j + 1])
            {
                t = x[j];
                x[j] = x[j + 1];
                x[j + 1] = t;
            }
        }
    }
    printf("\n");
}

实验4

#include <stdio.h>
#define N 100
void dec2n(int x, int n);
int main() {
int x;
printf("输入一个十进制整数: ");
while (scanf_s("%d", &x) != EOF) {
dec2n(x, 2);
dec2n(x, 8);
dec2n(x, 16);
printf("\n输入一个十进制整数: ");
}
return 0;
}
void dec2n(int n, int m)
{
char ans[100];
char a[16] = { '0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F' };
int i = 0;
do
{
ans[i++] = n % m;
n = n / m;
} while (n);
for (i--; i >= 0; i--)
printf("%c", a[ans[i]]);
printf("\n");
return 0;
}

 

 实验5

#include <stdio.h>
#define N 100
// 函数声明
void func(int x[][N], int n); // 注意：两维数组作为形参的语法
void output(int x[][N], int n); // 注意：两维数组作为形参的语法
int main()
{
    int x[N][N];
    int i, j, n;
    printf("Enter n: ");
    while (scanf_s("%d", &n) != EOF) {
        func(x, n); // 注意：两维数组作为实参的语法
        output(x, n); // 注意：两维数组作为实参的语法
        printf("\nEnter n: ");
    }
    return 0;
}
// 函数定义
// 功能：输出两维数组x中的数据，数据项n行、n列
void output(int x[][N], int n) {
    int i, j;
    for (i = 0; i < n; ++i) {
        for (j = 0; j < n; ++j)
            printf("%5d", x[i][j]);
        printf("\n");
    }
}
void func(int x[][N], int n)
{
    int i, j;
    for (i = 0; i < n; i++)
    {
        for (j = i; j < n; j++)
        {
            x[i][j] = i + 1;
        }
    }
    for (j = 0; j < n; j++)
    {
        for (i = j; i < n; i++)
        {
            x[i][j] = j + 1;
        }
    }
}

实验6

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>
#define N 80
int main() {
    char views1[N] = "hey, C, I have not love u yet.";
    char views2[N] = "hey, C, how can I love u?";
    char t[N];
    printf("交换前: \n");
    printf("views1: %s\n", views1);
    printf("views2: %s\n", views2);
    // 交换
    strcpy(t, views1);
    strcpy(views1, views2);
    strcpy(views2, t);
    printf("交换后: \n");
    printf("views1: %s\n", views1);
    printf("views2: %s\n", views2);
    return 0;
}

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>
#define N 80
int main() {
    char views[2][N] = { "hey, C, I have not love u yet.",
        "hey, C, how can I love u?" };
    char t[N];
    printf("交换前: \n");
    printf("views1: %s\n", views[0]);
    printf("views2: %s\n", views[1]);
    // 交换
    strcpy(t, views[0]);
    strcpy(views[0], views[1]);
    strcpy(views[1], t);
    printf("交换后: \n");
    printf("views1: %s\n", views[0]);
    printf("views2: %s\n", views[1]);
    return 0;
}

实验7

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>
#define N 5
#define M 20
void bubble_sort(char str[][M], int n); // 函数声明
int main() {
    char name[][M] = { "Bob", "Bill", "Joseph", "Taylor", "George" };
    int i;
    printf("输出初始名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);
    printf("\n排序中...\n");
    bubble_sort(name, N); // 函数调用
    printf("\n按字典序输出名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);
    return 0;
}
void bubble_sort(char str[][M], int n)
{
    int i, j;
    char b[100];
    for (int i = 0; i < n; i++)
        for (int j = i + 1; j < n; j++)
        {
            if (strcmp(str[i], str[j]) > 0)
            {
                strcpy(b, str[i]);
                strcpy(str[i], str[j]);
                strcpy(str[j], b);
            }
        }
}