hdu 1049 （很水的贪心）

View Code  1 #include<iostream> 
 2 #include<cstdio>
 3 #include<math.h>
 4 using namespace std;
 5 int main()
 6 {
 7     int n,u,d;
 8     while(cin>>n>>u>>d)
 9     {
10         if(n+u+d==0)
11             break;
12         int ans=(int)(ceil((n-u)*1.0/(u-d)))*2+1;
13         printf("%d\n",ans);
14     }
15     return 0;
16