有关判断表情的正则表达式

直接上代码了，用于判断字符串中是否有表情

public class EmojiUtils {
    /** * 检测是否有emoji表情 * @param source * @return */
    public static boolean containsEmoji(String source) {
        int len = source.length();
        for (int i = 0; i < len; i++) {
            char codePoint = source.charAt(i);
            if (!isEmojiCharacter(codePoint)) { //如果不能匹配,则该字符是Emoji表情
                return true;
            }
        }
        return false;
    }


    /** * 判断是否是Emoji * @param codePoint 比较的单个字符 * @return */
    private static boolean isEmojiCharacter(char codePoint) {
        return (codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA) || (codePoint == 0xD)
                || ((codePoint >= 0x20) && (codePoint <= 0xD7FF))
                || ((codePoint >= 0xE000) && (codePoint <= 0xFFFD))
                || ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF));
    }
}

直接使用就ok了，哈哈哈哈哈哈哈