第九次作业

#include <stdio.h>
main()
{
    int a[8], i, j;
    for (i = 0; i < 8; i++)
    {
        printf("请输入第 %d数字", i + 1);
        scanf_s("%d", &a[i]);
    }
    for (j = 7; j >= 0; j--)
    {
        printf("第%d个数字是 %d\n", j, a[j]);

    }
}

 

 

#include <stdio.h>
main()
{
int a[6], i, j, max, min, maxidx = 0, minidx = 0;
for (i = 0; i < 6; i++)
{
printf("请输入第%d的数:", i + 1);
scanf_s("%d", &a[i]);
}
max = a[0];
min = a[0];
for (j = 0; j < 6; j++)
{
if (max < a[j])
{
max = a[j];
maxidx = j;
}
if (min > a[j])
{
min = a[j];
minidx = j;
}
}
printf("最大的数为%d,下标为%d,最小的数为%d,下标为%d \n", max, maxidx, min, minidx);
}

 

 

 

 

 

#include <stdio.h>
main()
{
int i, a[10] = { 1,1 }, sum = 0;
for (i = 2; i < 10; i++)
{
a[i] = a[i - 1] + a[i - 2];
sum += a[i];
}
sum = sum + a[0] + a[1];
printf("前十项的和为%d\n", sum);
}

 

 

 

 

 

 

#include <stdio.h>
main()
{
int i, a[10] = { 1,1 }, sum = 0;
for (i = 2; i < 10; i++)
{
a[i] = a[i - 1] + a[i - 2];
sum += a[i];
}
sum = sum + a[0] + a[1];
printf("前十项的和为%d\n", sum);
}

 

 

 

 

#include <stdio.h>
main()
{
int i, j, a[3][4];
printf("请输入你的 12个数:\n");
for (i = 0; i < 3; i++)
{
for (j = 0; j < 4; j++)
{

scanf_s("%d", &a[i][j]);

}
}
printf("矩阵是:\n");
for (i = 0; i < 3; i++)
{
for (j = 0; j < 4; j++)
{
printf("%d\t", a[i][j]);
}
printf("\n");
}
}

 

 

 

 

 

 

#include <stdio.h>
main()
{
int m[5][5]={{1,2,3,4,5},{6,7,8,9,10},{11,12,13,14,15},{16,17,18,19,20},{21,22,23,24,25}};
int i,j,sum=0;
for ( i=0;i<5;i++ )
{
for ( j=0;j<5;j++ )
{
if ( i==j||i+j==4 )
{
sum+=m[i][j];
}
}
}

#include <stdio.h>
main()
{
int m[5][5]={{1,2,3,4,5},{6,7,8,9,10},{11,12,13,14,15},{16,17,18,19,20},{21,22,23,24,25}};
int i,j,sum=0;
for ( i=0;i<5;i++ )
{
for ( j=0;j<5;j++ )
{
if ( i==j||i+j==4 )
{
sum+=m[i][j];
}
}
}
printf ( "对角线的和:%d\n",sum );
}

 

 

 

#include <stdio.h>
main()
{
int a[5];
int i,sum=0;
double avg;
for ( i=0;i<5;i++ )
{
printf ( "please enter the %d number for score:",i+1 );
scanf ( "%d",&a[i] );
sum+=a[i];
}

 

 

 

 

 

 

 

 

 

 

posted @ 2021-12-01 21:15  王欣彤  阅读(22)  评论(0)    收藏  举报