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$.ajax()传递请求参数 

<!DOCTYPE html>
<html lang="en">

<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
</head>

<body>
    <button id="btn">发送请求</button>

    <script src="/js/jquery.min.js"></script>
    <script>
        var params = {
            name: 'zs',
            age: 18
        }
        $('#btn').on('click', function() {
            // console.log(1);
            $.ajax({
                type: 'post',
                url: '/user',
                // data: {
                //     name: 'zs',
                //     age: 18
                // },
                // data: 'name=zs&age=18',
                data: JSON.stringify(params),
                contentType: 'application/json',
                success: function(response) {
                    console.log(response);
                },
                error: function(xhr) {
                    console.log(xhr);
                }
            })
        })
    </script>
</body>

</html>

 

posted on 2022-09-29 20:55  生于理想  阅读(229)  评论(0)    收藏  举报