jQuery 获取元素当前位置offset()与position() 

<!DOCTYPE html>
<html lang="zh-CN">

<head>
  <meta charset="UTF-8">
  <title>Title</title>
  <style>
    * {
      margin: 0;
      padding: 0;
    }
    .father {
      width: 400px;
      height: 400px;
      background-color: pink;
      position: relative;
      margin: 100px;
    }
    .son {
      width: 200px;
      height: 200px;
      background-color: red;
      position: absolute;
      top: 100px;
      left: 100px;
    }
  </style>
</head>
<body>
  <div class="father">
    <div class="son"></div>
  </div>
  <script src="jquery-1.12.4.js"></script>
  <script>
    $(function () {

      //获取元素的相对于document的位置
      console.log($(".son").offset());
      console.log($(".son").offset().left);
      console.log($(".son").offset().top);
      //设置元素的left和top
      $(".son").offset({
        left: 300,
        top: 300
      })
      //函数方式的去设置 
      $(".son").offset(function (v, i) {
        var a = {};
        a.left = 400;
        a.top = 400;
        return a;
      })
      //获取元素相对于有定位的父元素的位置
      console.log($(".son").position());
      console.log($(".son").position().left);
      console.log($(".son").position().top);
    });
  </script>
</body>
</html>

 

 
posted @ 2019-04-28 15:41  py-小白  阅读(11360)  评论(0)    收藏  举报