Java数组遍历输出其中的最大值和最小值

 1 //输出最大值
 2 int[] num = {1, 2, 3, 4, 5, 1000, 1000000};
 3 int cc = num.length;
 4 int max = num[0];
 5 for (int i = 1; i < cc; i++) {
 6     if (num[i] > max) {
 7         max = num[i];
 8     }
 9 }
10 System.out.println("最大值" +  max);
11 
12 
13 
14 //输出最小值
15 int[] num1 = {1, 2, 3, 4, 5, 1000, 1000000};
16 int dd = num1.length;
17 int min = num1[0];
18 for (int i = 1; i < dd; i++) {
19     if (num1[i] < min) {
20         min = num1[i];
21     }
22 }
23 System.out.println("最小值" + min);

posted on 2021-01-05 21:04 wangchw 阅读(775) 评论(0) 编辑收藏举报