计算一个数的整数幂

#include<iostream>
#include<string.h> 
#include<limits.h>
#include<float.h>
#include<stdio.h>
#pragma warning(disable  : 4996)

using namespace std;

double power(double n, int p);
int main() {
    double x, xpow;
    int exp;
    printf("Enter a number and the positive integer power");
    printf("to which\nthe number will be rasised.Enter q");
    printf("to quit.\n");
    while (scanf("%lf%d",&x,&exp)==2)
    {
        xpow = power(x, exp);
        printf("%.3g to the power %d is %.5g\n", x, exp, xpow);
        printf("Enter next pair of numbers or q to quit.\n");
    }
    printf("Hope you enjoyed this power trip --bye!\n");
    return 0;

}

double power(double n, int p) {
    double pow = 1;
    for (int i = 0; i < p; i++)
    {
        pow *= n;
    }
    return pow;
}

posted @ 2022-10-17 11:05  江南王小帅  阅读(40)  评论(0)    收藏  举报