[AcWing 1096] 地牢大师

三维迷宫

BFS + 结构体存储

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点击查看代码

#include<bits/stdc++.h>

using namespace std;

typedef long long LL;

const int N = 100 + 10;
const int INF = 0x3f3f3f3f;

int L, R, C;
char g[N][N][N];
int d[N][N][N];
int dx[] = {-1, 1, 0, 0, 0, 0};
int dy[] = {0, 0, -1, 1, 0, 0};
int dz[] = {0, 0, 0, 0, -1, 1};

struct Node
{
    int x, y, z;
};

void bfs(Node sp, Node ep)
{
    memset(d, 0x3f, sizeof d);
    queue<Node> q;
    q.push(sp);
    d[sp.x][sp.y][sp.z] = 0;
    while (q.size()) {
        auto t = q.front();
        q.pop();
        for (int i = 0; i < 6; i ++) {
            int a = t.x + dx[i];
            int b = t.y + dy[i];
            int c = t.z + dz[i];
            if (a < 0 || a >= L || b < 0 || b >= R || c < 0 || c >= C)
                continue;
            if (d[a][b][c] != INF || g[a][b][c] == '#')
                continue;
            d[a][b][c] = d[t.x][t.y][t.z] + 1;
            q.push({a, b, c});
        }
    }
}

void solve()
{
    while (cin >> L >> R >> C, L) {
        Node sp, ep;
        for (int i = 0; i < L; i ++)
            for (int j = 0; j < R; j ++)
                for (int k = 0; k < C; k ++) {
                    cin >> g[i][j][k];
                    if (g[i][j][k] == 'S')
                        sp = {i, j, k};
                    if (g[i][j][k] == 'E')
                        ep = {i, j, k};
                }
        bfs(sp, ep);
        int dist = d[ep.x][ep.y][ep.z];
        if (dist == INF)
            printf("Trapped!\n");
        else
            printf("Escaped in %d minute(s).\n", dist);
    }
}

signed main()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    solve();

    return 0;
}

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1. 用结构体来存点的坐标，上下左右前后六个方向可以移动