[AcWing 1012] 友好城市


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#include<iostream>
#include<algorithm>
#define fi first
#define se second
using namespace std;
const int N = 5010;
int n;
int f[N];
pair<int,int> p[N];
int main()
{
cin >> n;
for (int i = 1; i <= n; i ++) {
int a, b;
cin >> a >> b;
p[i] = {a, b};
}
sort(p + 1, p + n + 1);
int res = 0;
for (int i = 1; i <= n; i ++) {
f[i] = 1;
for (int j = 1; j < i; j ++) {
if (p[i].se > p[j].se)
f[i] = max(f[i], f[j] + 1);
}
res = max(res, f[i]);
}
cout << res << endl;
return 0;
}
- 保证任意两条航线不相交的条件:
任意两个航线 \((a_1, b_1)\) 和 \((a_2, b_2)\) ,都必须满足
① $if \ \ a_1 < a_2 \ \ then \ \ b_1 < b_2 $
② $if \ \ a_1 > a_2 \ \ then \ \ b_1 > b_2 $ - 同时考虑两个坐标的最长上升子序列

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