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#include<iostream>
using namespace std;
const int N = 1e5 + 10;
int a[N];
int main()
{
int n, k;
scanf("%d %d", &n, &k);
for (int i = 0; i < n; i++) scanf("%d", &a[i]);
while (k--) {
int x;
scanf("%d", &x);
int l = 0, r = n - 1;
while (l < r) {
int mid = l + r >> 1;
if (a[mid] >= x) r = mid;
else l = mid + 1;
}
if (a[l] != x) printf("-1 -1\n");
else {
printf("%d ", l);
int l = 0, r = n - 1;
while (l < r) {
int mid = l + r + 1 >> 1;
if (a[mid] <= x) l = mid;
else r = mid - 1;
}
printf("%d\n", l);
}
}
return 0;
}
- 用到了两个二分模板,当更新公式为 l = mid 时,需要 mid = l + r + 1 >> 1;