实验4 数组应用编程

实验任务1.1

#include<stdio.h>
#define N 4
int main()
{
    int a[N] = { 1,9,8,4 };
    char b[N] = { '1','9','8','4' };
    int i;
    printf("sizeof(int)=%d\n", sizeof(int));
    printf("sizeof(char)=%d\n", sizeof(char));
    printf("\n");
    // 输出数组a中每个元素的地址、值 
    for (i = 0; i < N; i++)
        printf("%p;%d\n", &a[i], a[i]);
    printf("\n");
    // 输出数组b中每个元素的地址、值 
    for (i = 0; i < N; i++)
        printf("%p:%c\n", &b[i], b[i]);
    printf("\n");
    // 输出数组名a和b对应的值 
    printf("a=%p\n", a);
    printf("b=%p\n", b);
    return 0;
}

a是连续存放的，每个元素占4个内存字节单元.

b是连续存放的，每个元素占1个内存字节单元.

都是一样的。

实验任务1.2

#include<stdio.h>
#define N 2
#define M 4
int main()
{
    int a[N][M] = { {1,9,8,4}, {2,0,2,2} };
    char b[N][M] = { {'1','9','8','4'},{'2','0','2','2'} };
    int i, j;
    for (i = 0; i < N; i++)
        for (j = 0; j < M; j++)
            printf("%p:%d\n", &a[i][j], a[i][j]);
    printf("\n");
    for (i = 0; i < N; i++)
        for (j = 0; j < M; j++)
            printf("%p:%c\n", &b[i][j], b[i][j]);
    return 0;
}

a不是按行连续存放的，每个元素占4个内存字节单元.

b不是按行连续存放的，每个元素占1个内存字节单元.

实验任务2

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define N 13
int days_of_year(int year, int month, int day);
int main()
{
    int year, month, day;
    int days;
    while (scanf("%d%d%d", &year, &month, &day) != EOF)
    {
        days = days_of_year(year, month, day);
        printf("%4d-%02d-%02d是这一年的第%d天\n\n", year, month, day, days);

    }
    return 0;
}
int days_of_year(int year, int month, int day)
{
    int mont[13]={0};
    int i,aount,sum=0;
    for (i = 1; i < 13; i++)
    {
        if (i == 1 || i == 3 || i == 5 || i == 7 || i == 8 || i == 10 || i == 12)
            mont[i] = 31;
        else if (i == 4 || i == 6 || i == 9 || i == 11)
            mont[i] = 30;
        else if (i == 2)
            mont[i] = (((year % 4 == 0) && (year % 100 != 0) )|| (year % 400==0)) ? 29 : 28;
    }
    for (i = 1; i < month; i++)
            sum += mont[i];
    return sum + day;
}

 

实验任务3

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define N 5
void input(int x[], int n);
void output(int x[], int n);
double average(int x[], int n);
void bubble_sort(int x[], int n);
int main()
{
    int scores[N];
    double ave;
    printf("录入%d个分数:\n");
    input(scores, N);
    printf("\n输出课程分数: \n");
    output(scores, N);
    printf("\n课程分数处理: 计算均分、排序...\n");
        ave = average(scores, N);
    bubble_sort(scores, N);
    printf("\n输出课程均分: %.2f\n", ave);
    printf("\n输出课程分数(高->低):\n");
    output(scores, N);
    return 0;
}
void input(int x[], int n)
{
    int i;
    for (i = 0; i < n; i++)
        scanf("%d", &x[i]);
}
void output(int x[], int n)
{
    int i;
    for (i = 0; i < n; i++)
        printf("%4d", x[i]);
    printf("\n");
}
double average(int x[], int n)
{
    int i;
    double  sum = 0;
    for (i = 0; i < N; i++)
        sum += x[i];
    return sum / 5;
}
void bubble_sort(int x[], int n)
{
    int i, j,t;
    for (i = 0; i < n - 1; i++)
        for (j = 0; j < n - 1 - i; j++)
            if (x[i] < x[i + 1])
            {
                t = x[i];
                x[i] = x[i + 1];
                x[i + 1] = t;
            }
}

实验任务4

 

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define N 100
void dec2n(int x, int n);
int main()
{
    int x;
    printf("输入一个十进制整数:");
    while (scanf("%d", &x) != EOF)
    {
        dec2n(x, 2);
        dec2n(x, 8);
        dec2n(x, 16);
        printf("\n输入一个十进制整数:");
    }
    return 0;
}
void dec2n(int x, int n)
{
    char dic[100]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
    char aa[100]={0};
    int i = 0;
    while (x != 0)
    {
        aa[i++] = dic[x % n];
        x = x / n;
    }
    while (i >= 0) {
        printf("%c", aa[i - 1]);
        i--;
    }
    printf("\n");
}

实验任务5

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define N 100
void func(int x[][N], int n);
void output(int x[][N], int n);
int main()
{
    int x[N][N];
    int i, j, n;
    printf("Enter n:");
    while (scanf("%d", &n) != EOF)
    {
        func(x, n);
        output(x, n);
        printf("\nEnter n:");
    }
    return 0;
}
void output(int x[][N], int n)
{
    int i, j;
    for (i = 0; i < n; i++)
    {
        for (j = 0; j < n; j++)
            printf("%5d", x[i][j]);
        printf("\n");
    }
}
void func(int x[][N], int n)
{
    int i, j;
    for(i=0;i<n;i++)
        for (j = 0; j < n; j++)
        {
            if (i < j)
                x[i][j] = i + 1;
            else
                x[i][j] = j + 1;
        }
}

实验任务6.1

 

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>
#define N 80
int main()
{
    char views1[N] = "hey,C,l have not love u yet.";
    char views2[N] = "hey,C,how can l love u?";
    char t[N];
    printf("交换前：\n");
    printf("views1:%s\n", views1);
    printf("views2:%s\n", views2);
    //交换 交换
    strcpy(t, views1);
    strcpy(views1, views2);
    strcpy(views2, t);
    //交换后
    printf("交换后：\n");
    printf("views1:%s\n", views1);
    printf("views2:%s\n", views2);

    return 0;

}

实验任务6.2

 

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>
#define N 80
int main()
{
    char views[2][N] = { "hey,C,l have not love u yet.","hey,C,how can l love u?" };
    char t[N];

    printf("交换前:\n");
    printf("views1:%s\n", views[0]);
    printf("views2:%s\n", views[1]);

    //交换交换
    strcpy(t, views[0]);
    strcpy(views[0], views[1]);
    strcpy(views[1], t);

    printf("交换后:\n");
    printf("views1:%s\n", views[0]);
    printf("views2:%s\n", views[1]);

    return 0;
}

实验任务7

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>
#define N 5
#define M 20
void bubble_sort(char str[][M], int n);
int main()
{
    char name[][M] = { "Bob","Bill","Joseph","Taylor","George" };
    int i;
    printf("输入初始名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);
    printf("\n排序中...\n");
    bubble_sort(name, N);
    printf("\n按字母序输出名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);
    return 0;
}
void bubble_sort(char str[][M], int n)
{
    int i, j;
    char t[M]={'\0'};
    for(i=0;i<n-1;i++)
        for (j = 0; j < n - 1 - i; j++)
            if (strcmp(str[j],str[j+1])>0)
            {
                strcpy(t, str[j]);
                strcpy(str[j], str[j + 1]);
                strcpy(str[j + 1], t);
            }

}