买卖股票的最佳时机
2017-03-09 15:09 1500802028 阅读(133) 评论(0) 收藏 举报
class Solution {
public:
/**
* @param prices: Given an integer array
* @return: Maximum profit
*/
int maxProfit(vector<int> &prices) {
// write your code here
int ret = 0;
if(prices.size()<2)
return ret;
int lowest = prices[0];
for(int i=1;i<prices.size();i++)
{
int cur = prices[i];
ret = max(ret,cur-lowest);
lowest = min(lowest,cur);
}
return ret;
}
};
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