poj 2231 Moo Volume

Moo Volume
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 15037   Accepted: 4342

Description

Farmer John has received a noise complaint from his neighbor, Farmer Bob, stating that his cows are making too much noise.

FJ's N cows (1 <= N <= 10,000) all graze at various locations on a long one-dimensional pasture. The cows are very chatty animals. Every pair of cows simultaneously carries on a conversation (so every cow is simultaneously MOOing at all of the N-1 other cows). When cow i MOOs at cow j, the volume of this MOO must be equal to the distance between i and j, in order for j to be able to hear the MOO at all. Please help FJ compute the total volume of sound being generated by all N*(N-1) simultaneous MOOing sessions.

Input

* Line 1: N

* Lines 2..N+1: The location of each cow (in the range 0..1,000,000,000).

Output

There are five cows at locations 1, 5, 3, 2, and 4.

Sample Input

5
1
5
3
2
4

Sample Output

40

Hint

INPUT DETAILS:

There are five cows at locations 1, 5, 3, 2, and 4.

OUTPUT DETAILS:

Cow at 1 contributes 1+2+3+4=10, cow at 5 contributes 4+3+2+1=10, cow at 3 contributes 2+1+1+2=6, cow at 2 contributes 1+1+2+3=7, and cow at 4 contributes 3+2+1+1=7. The total volume is (10+10+6+7+7) = 40.
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int cows[10000];
int n;
int i,j;
__int64 sum=0;
scanf("%d",&n);
for(i=0;i<n;i++)
scanf("%d",&cows[i]);
for(i=0;i<n;i++)
{
for(j=i+1;j<n;j++)
{
sum+=2*abs(cows[j]-cows[i]);
}
}
printf("%I64d\n",sum);
return 0;
}
posted @ 2011-11-22 08:44  w0w0  阅读(158)  评论(0)    收藏  举报