Single Number

Single Number

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Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime c

位操作, 找出数组中的单数, 双数是成对的数, 单数是只有一个数, 如 1 1 2 2 3 3 5 5 4

单数就是4

class Solution {
public:
    int singleNumber(int A[], int n) {
        int i=0;
        int single = 0;
        while(i!=n)
        {
            single = single^A[i];
            i++;
        }
        return single;
    }
};