XML技巧大汇总

1.如何快速将一个XMLDocument的数据交换到另外一个XMLDocument?
<script language="jscript">
        var xmldoc1 = new ActiveXObject("Msxml2.DOMDocument");
        var xmldoc2 = new ActiveXObject("Msxml2.DOMDocument");
        xmldoc1.loadXML("<Data>1001</Data>");
        xmldoc1.save(xmldoc2);
    </script>

2.快速创建编码给一个XML文档?
var xmlItems = new ActiveXObject("Microsoft.XMLDOM");
var  pi;
pi = xmlItems.createProcessingInstruction("xml", "version='1.0' encoding='GB2312' ");
xmlItems.appendChild(pi);

3.利用Xslt把转换的结果放到别外一个XmlDocument？
 var source = new ActiveXObject("Msxml2.DOMDocument");
source.async = false;
source.loadXML(x)
alert(source.xml)

// 装载样式单
var stylesheet = new ActiveXObject("Msxml2.DOMDocument");
stylesheet.async = false;
stylesheet.resolveExternals = false;
stylesheet.load("style.xsl");
alert(stylesheet.xml)

// 创建结果对象
var result = new ActiveXObject("Msxml2.DOMDocument");
result.async = false;

// 把解析结果放到结果对象中方法1
source.transformNodeToObject(stylesheet, result);
alert(result.xml)

// 把解析结果放到结果对象中方法2
result2 = ""
result2 = source.transformNode(stylesheet);
source.loadXML(result2)
alert(source.xml)