struct可以拥有class般的构造函数
struct A
{
int a, b;
A(int x, int y) :a(x), b(y){}
};
int main()
{
A a(1, 2);
cout << a.a << " " << a.b << endl;
}
struct A
{
int a, b;
A(int x, int y) :a(x), b(y){}
};
int main()
{
A a(1, 2);
cout << a.a << " " << a.b << endl;
}