实验3

task1

`#include <stdio.h>

include <stdlib.h>

include <time.h>

include <windows.h>

define N 80

void print_text(int line, int col, char text[]); // 函数声明
void print_spaces(int n); // 函数声明
void print_blank_lines(int n); // 函数声明

int main() {
int line, col, i;
char text[N] = "hi, April~";

srand(time(0)); // 以当前系统时间作为随机种子

for(i = 1; i <= 10; ++i) {
    line = rand() % 25;
    col =  rand() % 80;
    print_text(line, col, text);
    Sleep(1000);  // 暂停1000ms
}

return 0; 

}

// 打印n个空格
void print_spaces(int n) {
int i;

for(i = 1; i <= n; ++i)
    printf(" ");

}

// 打印n行空白行
void print_blank_lines(int n) {
int i;

for(i = 1; i <= n; ++i)
    printf("\n");

}

// 在第line行第col列打印一段文本
void print_text(int line, int col, char text[]) {
print_blank_lines(line-1); // 打印(line-1)行空行
print_spaces(col-1); // 打印(col-1)列空格
printf("%s", text); } // 在第line行、col列输出text中字符串`


函数实现的功能是在25行,80列之内的随机位置生成10个不同位置的hi, April~,并且每次输出间隔一秒。

task 2(1)

`#include <stdio.h>

include<stdlib.h>

long long fac(int n); // 函数声明

int main() {
int i, n;

printf("Enter n: ");
scanf("%d", &n);

for (i = 1; i <= n; ++i)
    printf("%d! = %lld\n", i, fac(i));

system("pause");
return 0;

}

// 函数定义
long long fac(int n) {
static long long p = 1;
printf("p = %lld\n",p);
p = p * n;

return p;

}`

task2(2)

`#include <stdio.h>

include<stdlib.h>

int func(int, int); // 函数声明

int main() {
int k = 4, m = 1, p1, p2;

p1 = func(k, m);    // 函数调用
p2 = func(k, m);    // 函数调用
printf("%d, %d\n", p1, p2);

system("pause");
return 0;

}

// 函数定义
int func(int a, int b) {
static int m = 0, i = 2;

i += m + 1;
m = i + a + b;

return m;

}`

结果与分析的结果一致
局部static变量的特性:对变量只进行第一次的初始化,之后保留变量变化后的值

task3

`#include <stdio.h>
long long func(int n); // 函数声明

int main() {
int n;
long long f;

while (scanf("%d", &n) != EOF) {
    if (n<0||n>32)
        {printf("Error,n>=0&&n<=32");
    break;}
    else
    f = func(n); // 函数调用
    printf("n = %d, f = %lld\n", n, f);
}

return 0;

}

// 函数定义
long long func(int n){
if(n==0)
return 0;
else
return 2*(func(n-1)+1)-1;
}`

task4(1)

`#include <stdio.h>
int func(int n, int m);
int func1(int x);

int main() {
int n, m;

while(scanf("%d%d", &n, &m) != EOF)
    printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m));

return 0;

}
int func1(int x){
int i,j=1;
for(i=1;i<=x;i++){
j=j*i;
}
return j;
}

int func(int n,int m){
return func1(n)/(func1(m)*func1(n-m));
}`

task4(2)

`#include <stdio.h>
int func(int n, int m);

int main() {
int n, m;

while(scanf("%d%d", &n, &m) != EOF)
    printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m));

return 0;

}

int func(int n,int m){
if(n<m)
return 0;
if(m == 0 || n == m)
return 1;
else
return func(n-1,m-1)+func(n-1,m);
}`

task5

`#include<stdio.h>

include<stdlib.h>

include<math.h>

void hanoi(unsigned int n,char from,char temp,char to);
void moveplate(unsigned int n,char from,char to);
int main()
{
float n;
int x;
while((scanf("%f",&n))!=EOF)
{hanoi(n,'A','B','C');
x = pow(2,n)-1;
printf("一共移动了%d次\n",x);}
system("pause");
return 0;
}
void hanoi(unsigned int n,char from,char temp,char to){
if(n==1)
moveplate(n,from,to);
else
{
hanoi(n-1,from,to,temp);
moveplate(n,from,to);
hanoi(n-1,temp,from,to);}
}
void moveplate(unsigned int n,char from,char to){
printf("%u;%c-->%c\n",n,from,to);
}`

task6

`#include <stdio.h>

include <math.h>

long func(long s); // 函数声明

int main() {

long s, t;

printf("Enter a number: ");
while (scanf("%ld", &s) != EOF) {
    t = func(s); // 函数调用
    printf("new number is: %ld\n\n", t);
    printf("Enter a number: ");
}

return 0;

}
long func(long s){
int ans;
long digit,t;
ans = 0;
t =1;
while(s!=0){
digit = s%10;
if(digit%2!=0){
ans+=tdigit;
t
=10;
}
s/=10;
}
return ans;
}`

posted @ 2024-04-28 21:38  very241925  阅读(21)  评论(0)    收藏  举报