剑指 Offer 53 - II. 0~n-1中缺失的数字

class Solution {
public int missingNumber(int[] nums) {
if(nums.length < 1) return 0;
int l = 0;
int r = nums.length - 1;
while(l < r){
int mid = l + r >> 1;
if(nums[mid] != mid) r = mid;
else l = mid + 1;
}
if( r == nums[r]) r ++; //全部连续
return r;
}
}

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