使用idea创建springboot项目并打成war包发布到tomcat8上

1.将pom.xml中的打包方式修改为war 

<groupId>com.borya</groupId>
<artifactId>Project</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>war</packaging>

2.在pom.xml中添加依赖,将scope状态修改为provided

<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-tomcat</artifactId>
<scope>provided</scope>
</dependency>

3.修改src/main/java下的application启动项

package com.borya;

@SpringBootApplication
public class ProjectApplication extends SpringBootServletInitializer implements WebApplicationInitializer{

    @Override
    protected SpringApplicationBuilder configure(SpringApplicationBuilder application){

        return application.sources(ProjectApplication.class);
    }

    public static void main(String[] args) {
        SpringApplication.run(ProjectApplication.class, args);
    }
}

4.重新build项目

 

 5.菜单 Build -->> build artifacts -->> all artifacts -->> Build

6.此时项目已经成功打包成war包,位置在项目结构的target下,以.war结尾的就是项目

 

7.下面就是将项目发布到远程服务器上了,我这里使用的是WinSCP工具,登录成功后,直接将war包放到服务器tomcat下的webapps中,修改tomcat/conf中的server.xml

 

 

8.找到Host标签,在其中添加如下配置

<Context docBase="包名.war" path="/demo3" reloadable="true" debug="0" privileged="true" />

9.重启tomcat

重启可以理解为先关闭tomcat+再启动tomcat

sh shutdown.sh
sh startup.sh

 

 

posted @ 2018-02-01 23:17  威流  阅读(410)  评论(0编辑  收藏  举报