P1328 [NOIP2014 提高组] 生活大爆炸版石头剪刀布

题目链接

https://www.luogu.com.cn/problem/P1328

题目思路

用二维数组存每种情况的得分情况,然后枚举来计算分数

#include <iostream>

using namespace std;

int main() 
{
    int vs[5][5] = {{0, 0, 1, 1, 0}, {1, 0, 0, 1, 0}, {0, 1, 0, 0, 1}, {0, 0, 1, 0, 1}, {1, 1, 0, 0 , 0}};
    int n, na, nb;
    cin >> n >> na >> nb;
    int a[na], b[nb];

    for (int i = 0; i < na; i++)
        cin >> a[i];

    for (int i = 0; i < nb; i++)
        cin >> b[i];

    int wa = 0, wb = 0;
    for (int i = 0; i < n; i++) 
    {
        wa += vs[a[i % na]][b[i % nb]];
        wb += vs[b[i % nb]][a[i % na]];
    } 

    cout << wa << " " << wb << endl;

    return 0;
}