hdu1316 java解高精度斐波数
How Many Fibs?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3334 Accepted Submission(s): 1340
Problem Description
Recall the definition of the Fibonacci numbers:
f1 := 1
f2 := 2
fn := fn-1 + fn-2 (n >= 3)
Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b].
f1 := 1
f2 := 2
fn := fn-1 + fn-2 (n >= 3)
Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b].
Input
The input contains several test cases. Each test case consists of two non-negative integer numbers a and b. Input is terminated by a = b = 0. Otherwise, a <= b <= 10^100. The numbers a and b are given with no superfluous leading zeros.
Output
For each test case output on a single line the number of Fibonacci numbers fi with a <= fi <= b.
Sample Input
10 100 1234567890 9876543210 0 0
Sample Output
5 4
import java.math.BigDecimal;
import java.math.BigInteger;
import java.util.Scanner;
public class Main {
public static void main(String []args)throws Exception{
Scanner cin = new Scanner(System.in);
while(cin.hasNext()){
String a=cin.next();
String b=cin.next();
if(a.equals("0")&&b.equals("0"))
break;
BigInteger c = new BigInteger(a);
BigInteger d = new BigInteger(b);
int sum=fibo(c,d);
System.out.println(sum);
}
cin.close();
}
public static int fibo(BigInteger a,BigInteger b){
int sum =0;
BigInteger f = new BigInteger("1");
BigInteger s = new BigInteger("2");
while(true){
if(f.compareTo(b)>0)
break;
if(f.compareTo(a)>=0)
sum++;
BigInteger tem = f;
f=s;
s=s.add(tem);
}
return sum;
}
}
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