实验6

实验任务4

#include<stdio.h>
#define N 10
typedef struct{
    char isbn[20];
    char name[80];
    char author[20];
    double sales_price;
    int sales_count;
}Book;
void output(Book x[],int n);
void sort(Book x[],int n);
double sales_amount(Book x[],int n);
int main(){
    Book x[N]={{"978-7-5327-6082-4","门将之死","罗纳德.伦",42,51},
    {"978-7-308-17047-5","自由与爱之地：入以色列记","云也退",49,30},
    {"978-7-5404-9344-8","伦敦人","克莱格泰勒",68,27},
    {"978-7-5447-5246-6","软件体的生命周期","特德姜",35,90},
    {"978-7-5722-5475-8","芯片简史","汪波",74.9,49},
    {"978-7-5133-5750-0","主机战争","布莱克.J.哈里斯",128,42},
    {"978-7-2011-4617-1","世界尽头的咖啡馆","约翰.史崔勒基",22.5,44},
    {"978-7-5133-5109-6","你好外星人","英国未来出版集团",118,42},
    {"978-7-1155-0509-5","无穷的开始:世界进步的本源","戴维.多伊奇",37.5,55},
    {"978-7-229-14156-1","源泉","安.兰德",84,59}};
    printf("图书销量排名（按销售册数）：\n");
    sort(x,N);
    output(x,N);
    printf("\n图书销售总额：%.2f\n",sales_amount(x,N));
    return 0;
}

void sort(Book x[],int n){
    int i,j;
    Book temp;
    for(i=0;i<n-1;i++){
        for(j=0;j<n-1-i;j++){
            if(x[j].sales_count<x[j+1].sales_count){
                temp=x[j];
                x[j]=x[j+1];
                x[j+1]=temp;    
            }    
        }
    }
}
void output(Book x[],int n){
    int i;
    printf("%-20s%-30s%-20s%-10s%-10s\n","ISBN号","书名","作者","售价","销售册数");
    for(i=0;i<n;i++){
        printf("%-20s%-30s%-20s%-10g%-10d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
    }
}
double sales_amount(Book x[],int n){
    int i;
    double total=0;
    for(i=0;i<n;i++){
        total+=x[i].sales_price*x[i].sales_count;
    }
    return total;
}

实验任务5

#include<stdio.h>
typedef struct{
    int year;
    int month;
    int day;
}Date;
void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1,Date d2);
void test1(){
    Date d;
    int i;
    printf("输入日期：（以形如2025-12-19这样的方式输入）\n");
    for(i=0;i<3;++i){
        input(&d);
        printf("%d-%02d-%02d是这一年中的第%d天\n\n",d.year,d.month,d.day,day_of_year(d));
    }
}
void test2(){
    Date Alice_birth,Bob_birth;
    int i;
    int ans;
    printf("输入Alice和Bob的出生日期：（以形如2025-12-19这样的方式输入）\n");
    for(i=0;i<3;i++){
        input(&Alice_birth);
        input(&Bob_birth);
        ans=compare_dates(Alice_birth,Bob_birth);
        if(ans==0)
            printf("Alice和Bob一样大\n\n");
        else if(ans==-1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}
int main(){
    printf("测试1：输入日期，打印输出这是一年第多少天\n");
    test1();
    printf("\n测试2：两个人年龄大小关系\n");
    test2();
}
void input(Date *pd){
    scanf("%d-%02d-%02d",&pd->year,&pd->month,&pd->day);
}
int day_of_year(Date d){
    int count=0;
    int i;
    int x1[12]={31,29,31,30,31,30,31,31,30,31,30,31};
    int x2[12]={31,28,31,30,31,30,31,31,30,31,30,31};
    if((d.year%100!=0&&d.year%4==0)||(d.year%400==0)){
        for(i=0;i<d.month-1;i++){
            count+=x1[i];
        }
        count+=d.day;
    }
    if((d.year%4!=0)||(d.year%100==0&&d.year%400!=0)){
        for(i=0;i<d.month-1;i++){
            count+=x2[i];
        }
        count+=d.day;
    }
    return count;
}
int compare_dates(Date d1,Date d2){
    if(d1.year<d2.year){
        return -1;
    }
    else if(d1.year>d2.year){
        return 1;
    }
    else{
        if(d1.month<d2.month){
            return -1;
        }
        else if(d1.month>d2.month){
            return 1;
        }
        else{
            if(d1.day<d2.day){
                return -1;
            }
            else if(d1.day>d2.day){
                return 1;
            }
        }
    }
    return 0;
}

实验任务6

#include<stdio.h>
#include<string.h>
enum Role{admin,student,teacher};
typedef struct{
    char username[20];
    char password[20];
    enum Role type;
}Account;
void output(Account x[],int n);
int main(){
    Account x[]={{"A1001","123456",student},
    {"A1002","123abcdef",student},
    {"A1009","xyz12121",student},
    {"X1009","9213071x",admin},
    {"C11553","129dfg32k",teacher},
    {"X3005","921kfmg917",student}};
    int n;
    n=sizeof(x)/sizeof(Account);
    output(x,n);
    return 0;
}
void output(Account x[],int n){
    int i,j;
    int size[n]={0};
    for(i=0;i<n;i++){
        size[i]=strlen(x[i].password);
    }
    for(i=0;i<n;i++){
        for(j=0;j<size[i];j++){
            x[i].password[j]='*';
        }
        printf("%-20s%-20s",x[i].username,x[i].password);
        switch(x[i].type){
            case 0:printf("admin\n");break;
            case 1:printf("student\n");break;
            case 2:printf("teacher\n");break;
            default:break;
        }
    }
}

实验任务7

#include<stdio.h>
#include<string.h>
typedef struct{
    char name[20];
    char phone[12];
    int vip;
}Contact;
void set_vip_contact(Contact x[],int n,char name[]);
void output(Contact x[],int n);
void display(Contact x[],int n);
#define N 10
int main(){
    Contact list[N]={{"刘一","15510846604",0},
    {"陈二","18038747351",0},
    {"张三","18853253914",0},
    {"李四","13230584477",0},
    {"王五","15547571923",0},
    {"赵六","18856659351",0},
    {"周七","17705843215",0},
    {"孙八","15552933732",0},
    {"吴九","18077702405",0},
    {"郑十","18820725036",0}};
    int vip_cnt,i;
    char name[20];
    printf("显示原始通讯信息：\n");
    output(list,N);
    printf("\n输入要设置的紧急联系人个数：");
    scanf("%d",&vip_cnt);
    for(i=0;i<vip_cnt;++i){
        scanf("%s",name);
        set_vip_contact(list,N,name);
    }
    printf("\n显示通讯录列表：（按姓名字典序升序排列，紧急联系人最先显示）\n");
    display(list,N);
    return 0;    
}
void set_vip_contact(Contact x[],int n,char name[]){
    int i;
    for(i=0;i<n;++i){
        if(strcmp(x[i].name,name)==0){
            x[i].vip=1;    
        }
    }
}
void display(Contact x[],int n){
    int i,j;
    Contact temp;
    for(i=0;i<n-1;i++){
        for(j=0;j<n-1-i;j++){
            if(((strcmp(x[j].name,x[j+1].name)>0)&&(x[j].vip==x[j+1].vip))||x[j].vip<x[j+1].vip){
                temp=x[j];
                x[j]=x[j+1];
                x[j+1]=temp;
            }
        }
    }    
    output(x,n);
}
void output(Contact x[],int n){
    int i;
    for(i=0;i<n;++i){
        printf("%-10s%-15s",x[i].name,x[i].phone);
        if(x[i].vip)
            printf("%5s","*");
        printf("\n");
    }
}