实验6


#include<stdio.h>
#include<string.h> #define N 3 typedef struct student{ int id; char name[20]; char subject[20]; double perf; double mid; double final; double total; char level[10]; } STU; void input(STU [], int); void output(STU [],int); void calc(STU [],int); int fail(STU [],STU [], int); void sort(STU [],int); int main() { STU st[N],fst[N]; int k; printf("录入学生成绩信息:\n"); input(st,N); printf("\n成绩处理...\n"); calc(st,N); k = fail(st,fst,N); sort(st,N); printf("\n学生成绩排名情况:\n"); output(st,N); printf("\n不及格学生信息:\n"); output(fst,N); return 0; } void input(STU s[],int n){ int i; for(i = 0;i<n;i++) scanf("%d %s %s %lf %lf %lf",&s[i].id,s[i].name,s[i].subject,&s[i].perf,&s[i].mid,&s[i].final); } void output(STU s[],int n){ int i; printf("---------------\n"); printf("学号 姓名 科目 平时 期中 总评 等级\n"); for(i = 0;i<n;i++) printf("%d %-6s %-4s %-4.0f %-4.0f %-4.0f %-4.1f %s\n",s[i].id,s[i].name,s[i].subject,s[i].perf,s[i].mid,s[i].final,s[i].total,s[i].level); } void calc(STU s[], int n){ int i; for(i = 0;i<n;i++){ s[i].total = s[i].perf*0.2+s[i].mid*0.2+s[i].final*0.6; if(s[i].total>=90) strcpy(s[i].level,""); else if(s[i].total>=80&&s[i].total<90) strcpy(s[i].level,""); else if(s[i].total>=70&&s[i].total<80) strcpy(s[i].level,""); else if(s[i].total>=60&&s[i].total<70) strcpy(s[i].level,"及格"); else strcpy(s[i].level,"不及格"); } } int fail(STU s[],STU t[], int n){ int i,cnt = 0; for(i = 0;i<n;i++) if(s[i].total<60) t[cnt++] = s[i]; return cnt; } void sort(STU s[], int n){ int i, j; STU t; for(i = 0;i<n-1;i++) for(j = 0;j<n-1-i;j++) if(s[i].total<s[j+1].total){ t = s[j]; s[j] = s[j+1]; s[j+1] = t; } }

 

 

 

task 2

 

#include <stdio.h>
#include <string.h>
#define N 10
#define M 80

typedef struct {
    char name[M];
    char author[M];
} Book;

int main()
{
     Book x[N] = { {"《一九八四》", "乔治.奥威尔"},
                  {"《美丽新世界》", "赫胥黎"},
                  {"《昨日的世界》", "斯蒂芬.茨威格"}, 
                  {"《万历十五年》", "黄仁宇"},
                  {"《一只特立独行的猪》", "王小波"},
                  {"《百年孤独》", "马尔克斯"},
                  {"《查令十字街84号》", "海莲.汉芙"},
                  {"《只是孩子》", "帕蒂.史密斯"}, 
                  {"《刀锋》", "毛姆"},
                  {"《沉默的大多数》", "王小波"} };
    Book *ptr;
    int i;
    char author[M];
    
    printf("所有图书信息:\n");
    for(ptr = x;ptr<x+N;++ptr)
      printf("%-30s%-30s\n",ptr->name,ptr->author);
    
    printf("\n输入作者名:");
    gets(author);
    for(ptr = x;ptr<x+N;++ptr)
      if(strcmp(ptr->author,author) == 0){
          printf("%-30s%-30s\n",ptr->name,ptr->author);
      }
    return 0;
}

 

task 3_1

#include <stdio.h>
#include <stdlib.h>
#define N 80

typedef struct FilmInfo {
    char name[N];
    char director[N];
    char region[N];
    int year;
    struct FilmInfo *next;
} Film;


void output(Film *head);  
Film *insert(Film *head, int n);  


int main() {
    int n;         
    Film *head;   

    head = NULL;
    printf("输入影片数目: ");
    scanf("%d", &n);

    head = insert(head, n);

    printf("\n所有影片信息如下: \n");
    output(head);

    return 0;
}

Film *insert(Film *head, int n) {
    int i;
    Film *p;

    for(i = 1; i <= n; ++i) {
        p = (Film *)malloc(sizeof(Film));
        printf("请输入第%d部影片信息: ", i);
        scanf("%s %s %s %d", p->name, p->director, p->region, &p->year);
        
        p->next = head;
        head = p;  
    }

    return head;
}

void output(Film *head) {
    Film *p;

    p = head;
    while(p != NULL) {
        printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p->year);
        p = p -> next;
    }
}

task3_2

#include <stdio.h>
#include <stdlib.h>
#define N 80

typedef struct FilmInfo {
    char name[N];
    char director[N];
    char region[N];
    int year;
    struct FilmInfo *next;
} Film;


void output(Film *head);   
Film *insert(Film *head, int n);   


int main() {
    int n;          
    Film *head;    
    Film *p;       

    p = (Film *)malloc(sizeof(Film));
    p->next = NULL;
    head = p;       

    printf("输入影片数目: ");
    scanf("%d", &n);

    head = insert(head, n);

    printf("\n所有影片信息如下: \n");
    output(head);

    return 0;
}

Film *insert(Film *head, int n) {
    int i;
    Film *p;

    for(i = 1; i <= n; ++i) {
        p = (Film *)malloc(sizeof(Film));
        printf("请输入第%d部影片信息: ", i);
        scanf("%s %s %s %d", p->name, p->director, p->region, &p->year);

        p->next = head->next;
        head->next = p;
    }

    return head;
}

void output(Film *head) {
    Film *p;

    p = head->next;
    while(p != NULL) {
        printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p->year);
        p = p -> next;
    }
}

 

task 4

#include <stdio.h>
#define N 10

typedef struct {
    char isbn[20];          // isbn号
    char name[80];          // 书名
    char author[80];        // 作者
    double sales_price;     // 售价
    int  sales_count;       // 销售册数
} Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
    Book x[N] = {{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59},
                 {"978-7-5133-5261-1", "李白来到旧金山", "谭夏阳", 48, 16},
                 {"978-7-5617-4347-8", "陌生人日记", "周怡芳", 72.6, 27},
                 {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                 {"978-7-5046-9568-0", "数据化决策", "道格拉斯·W·哈伯德", 49, 42},
                 {"978-7-5133-4388-6", "美好时代的背后", "凯瑟琳.布", 34.5, 39},
                 {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                 {"978-7-5321-5691-7", "何为良好生活", "陈嘉映", 29.5 , 31},
                 {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                 {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}};
    
    printf("图书销量排名: \n");
    sort(x, N);
    output(x, N);

    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
    
    return 0;
}


void output(Book x[],int n){
    Book *p;
    printf("ISBN号               书名                           作者                   售价                 销售册数\n"); 
    for(p = x;p<x+n;p++){
        printf("%-20s %-30s %-20s %-20f %-20d\n",p->isbn,p->name,p->author,p->sales_price,p->sales_count);
    }
}



void sort(Book x[],int n){
    int i,j;
    Book t;
    for(i = 0;i<n-1;i++){
        for(j = 0;j<n-1-i;j++)
            if(x[j].sales_count<x[j+1].sales_count){
              t = x[j];
              x[j] = x[j+1];
              x[j+1] = t;    
            }
        
    }
}


double sales_amount(Book x[],int n){
    double s = 0;
    Book *p;
    for(p = x;p<x+n;p++){
        s = s + p->sales_count*p->sales_price;
    }
    return s;
}

 

task 5

 

#include <stdio.h>

typedef struct {
    int year;
    int month;
    int day;
} Date;

void input(Date* pd);                   
int day_of_year(Date d);                
int compare_dates(Date d1, Date d2);

void test1() {
    Date d;
    int i;
    printf("输入日期:(以形如2023-12-11这样的形式输入)\n");

    for (i = 0;i < 3;++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
    }
}

void test2() {
    Date Alice_birth, Bob_birth;
    int i;
    int ans;

    printf("输入Alice和Bob出生日期:(以形如2023-12-11这样的形式输入)\n");

    for (i = 0;i < 3;++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);

        if (ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if (ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}

int main()
{
    printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
    return 0;
}

void input(Date* pd) {
    scanf("%d-%d-%d", pd->year, pd->month, pd->day);
}

int day_of_year(Date d) {
    int m[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
    if ((d.year % 4 == 0 && d.year % 400 == 0) || d.year % 4 == 0) {
        m[2] = 29;

    }
    int sum = 0;
    int i;
    for (i = 1;i <= d.month;++i) {
        sum += m[i];
    }
    sum += d.day;
    return sum;
}

int compare_dates(Date d1, Date d2) {
    int ans;
    if (d1.year < d2.year) {
        ans = -1;
        return ans;

    }
    else if (d1.year > d2.year) {
        ans = 1;
        return ans;
    }
    else {
        if (d1.month < d2.month) {
            ans = -1;
            return ans;
        }
        if (d1.month > d2.month) {
            ans = 1;
            return ans;
        }
        else {
            if (d1.day < d2.day) {
                ans = -1;
                return ans;
            }
            if (d1.day > d2.day) {
                ans = 1;
                return ans;
            }
            else {
                ans = 0;
                return ans;
            }
        }
    }
}

 

 

 

task 6

#include <stdio.h>
#include <string.h>

enum Role {admin, student, teacher};

typedef struct {
    char username[20];  
    char password[20];  
    enum Role type;     
} Account;



void output(Account x[], int n);    

int main() {
    Account x[] = {{"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student}, 
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student}};
    int n;
    n = sizeof(x)/sizeof(Account);
    output(x, n);

    return 0;
}


void output(Account x[], int n) {
    int i,j;
    for(i = 0;i<n;++i){
        printf("%s\t",x[i].username);
        int s = strlen(x[i].password);
        for(j = 0;j<s;++j){
            printf("*");
        }
        if(s<7){
            printf("\t\t");
        }
        else{
            printf("\t");
        }
        switch(x[i].type){
            case admin:printf("admin");break;
            case student:printf("studen");break;
            case teacher:printf("teacher");break;
        }
        printf("\n");
    }
}

 

posted @ 2023-12-11 17:29  Gustave-Ehsy  阅读(21)  评论(0)    收藏  举报